Yes it is a requirement the presenter even said they wouldn't even consider applicants without a personal project.
I like the shed idea but unfortunately I live in a small apartment so this would be impossible, maybe this summer when I go home that would work. I'll check out your other ideas...
Hello!
So here is the deal. I went to a meeting on Industrial Experience job placement for engineering students where it's kind of like a co-op, they help you find internships in your field for summer work.
Anyways I know there is no way I can get in this year because one of the...
Its a simple set of linear equations.
Figure out 2 equations,
1)The distance Jimmy is from the origin
2) The distance Jenny is from the origin.
Equate and you'll get your answer.
Wow thank you very much! I see now how the other guys got the moment of inertia and I think I have it figured out. Will post once I get my marks back to see if I got it right.
Thank you once again!
Ok so solving for v I got 2.98m/s and since v=rw I got w=5.96. Thats the answer to A and I know to find b I apply the conservation of angular momentum. But for the life of me I can't figure out I for the sign or the snowball. Looking at that list I can't find any that fit the scenario with only...
Ok so I guess I'm confused as to how I find the angular momentum of the snowball before the collision if I'm not given a position vector. Unless the position vector is x=0 y=50cm?
Also how do I find the angular momentum of the sign without the rotational velocity (which is what I'm trying to...
Hello and thanks for the reply!
Yes I did mean conservation of mechanical energy, my bad. I was applying it to the first question though (angular speed of the sign immediately before impact) so the snowball doesn't have anything to do with that I think?
Homework Statement
Hi guys! I'm having trouble with this Problem. A thin uniform rectangular sign hangs vertically above the door of a shop. The sign is hinged to a stationary horizontal rod along its top edge. The mass of the sign is 2.40kg and its vertical dimension is 50.0cm. The sign is...