Recent content by Lida

Thanks!

My physics prof's father died last week, and rather than cancel class, a different prof taught our class (by different, I mean a different one each day). This assignment was emailed to us by the head of the physics department, who spent less than five minutes with the class, and did not explain...

Finally! Thanks! :biggrin:

I think the answer is 78.4 now...hopefully.

Now I figured 39.2 as my velocity and got 348.88 for the tower. This doesn't seem right, but I did that using the x-x0= v0t + 1/2at^2 equation. ( I'm using 192.08 for 1/2at^2) Using 19.6 instead of 192.08, because I think that might be where I'm going wrong, I end up with 176.4...

I multiplied 9.8 by 4 in an attempt to reverse the equation for acceleration.

With this formula I got 192.08m for the tower and 48.02m/s for my velocity. Closer?

Ok. I have a book called "How to Solve Physics Problems" and it uses 9.8 a lot for free falling objects, so I'm guessing that might be the acceleration of a falling object? If that's the case, then the shot tower is 39.2 m right? And I got that the velocity was 9.8 m/s, but I'm not so...

I dooooon't knooooow! :( Should it be obvious from the problem? I'm so confused by this. And thanks for the welcome. :)

Ball bearings can be made by leting shperical drops of molten metal fall inside a tall tower - called a shot tower- and solidify as they fall. If a bearing needs 4.0s to solidify enough for impact, how high must the tower be? What is the bearing's impact velocity? I've never taken a...