Confused - How do I find the static and kinetic friction coefficient?

AI Thread Summary
To find the static and kinetic friction coefficients, use the formula where the static coefficient is the friction force required to start movement divided by the object's weight, and the kinetic coefficient is the force needed to maintain movement divided by the object's weight. The readings from the force probe should be plugged into the equations, so for static friction, it would be calculated as static force (9.5N) divided by weight (17.5N). It's important to report weight in Newtons, as it represents force, while grams measure mass. This approach will help accurately determine the coefficients of friction for your lab assignment.
Lida
Messages
10
Reaction score
0
My physics prof's father died last week, and rather than cancel class, a different prof taught our class (by different, I mean a different one each day). This assignment was emailed to us by the head of the physics department, who spent less than five minutes with the class, and did not explain the lab that she assigned. Therefore, I'm doing a take home lab on friction, and need a few answers to complete it. Here are the instructions.

"The static coefficient of friction between two surfaces, υs, is equal to the friction force required to get the object moving divided by the object's weight. The kinetic coefficient of friction, uk, is equal to the force required to keep the object moving at the same velocity divided by the object's weight. Both coefficients are thus unitless and less than one. Using the force probe provided, measure the coefficient of static friction and the coefficient of kinetic friction between an object of your choice and five different surfaces. To do a good job, you will want to zero the probe, figure out a way to connect your object to the probe, and conduct multiple trials and average. All of the probes measure forces in "Newtons" or "grams". Read "Newtons". We ought never measure forces in "grams"."

I already did all the data collecting; here's one set:
I used my makeup case, weighing 1800g, or 17.5N, and hooked the probe to the handle on the top. On my linoleum floor, the average static force reading from the probe was 9.5N.

(I've attached a pic of my case on the linoleum floor)




From what the instructions say, static coefficient= force/weight and kinetic coefficient= force/weight.




My questions are:
1. is the reading from the probe my answer, or should I plug it into the equation like this? Static=9.5N/17.5N etc.

and

2. Should I give the weight of my case in Newtons or grams?

Thanks!
 

Attachments

  • 101_1068.jpg
    101_1068.jpg
    58 KB · Views: 531
Physics news on Phys.org
Lida said:
My questions are:
1. is the reading from the probe my answer, or should I plug it into the equation like this? Static=9.5N/17.5N etc.
The probe gives you the force (in Newtons); to get the coefficient you need to use force/weight (like you did).

2. Should I give the weight of my case in Newtons or grams?
Weight is a force, so it should be in Newtons. (Grams is a measure of mass, not weight.)
 
Thanks!
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top