Recent content by littlejon

What are the strength and direction of the electric field at the position indicated by the dot in the figure (Figure 1) ? Specify the strength of the electric field. Let r = 7.3cm . Express your answer using two significant figures. Thats word for word.

Then ((9E9)(2*.073*3E-9))/((.146^2)+(.073)^2)^(3/2) = 906?

Homework Statement Learning Goal:[/B] To practice Problem-Solving Strategy 26.1 for point chargeproblems. Three positively charged particles, with charges q1=q, q2=2q, and q3=q (where q>0), are located at the corners of a square with sides of length d. The charge q2 is located diagonally from...

Homework Statement Two 10-cm-diameter charged rings face each other, 25cm apart. The left ring is charged to -17nC and the right ring is charged to +17nC . A.What is the magnitude of the electric field E⃗ at the midpoint between the two rings?B.What is the magnitude of the force F⃗ on a -1.0...

Homework Statement Specify the strength of the electric field. Let r = 7.3cm . Homework Equations E1= (k*p)/(r^2+a^2)^3/2 Here k= constant used in Coulomb's law. a= half the length of dipole p= dipole moment = charge x length of dipole. Charge = 3nC and length of dipole The Attempt at a...

Okay since we know it not zero then if 8000 work is being done than is the problem reiterating the work that was done so A?

I just saw the wavelength and assumed it was 5.

I see so the answer has got to be E since we know its the same cylinder it would reduce the time by twice.

amplitude is 5

100 ceclius = 373k 200 celecius = 473k 473/373 = 1.3

confirm my doubts.

Homework Statement Homework Equations pv = nRt The Attempt at a Solution The answer is zero because it does not move since no work is being done.

Homework Statement Homework Equations pv=nRT The Attempt at a Solution Celsius and kelvin read the same so that means the pressure does not change because the gasses volume does not. C

Homework Statement Homework Equations pv = nrt The Attempt at a Solution TA = TB/2 Ta<Tb

Now that I look at it closely. The answer has got to be C because each oscillation is the same as the previous.