Recent content by lucasLima

I used the above equation and arrived in the result of 540 046 PA . Should I decompose Pj in x and y to know the amount of pressuire in each axis so I can put in the linear momentum equation (in the Pressure Force)? If so, how should I do that?

(V12)/2 + g*z1 + P1/p = (Vj2)/2 + g*zj + Pj/ 1000 z1=z2 V1= 12 P1=500 kPa and p = 1000 72+500 = (Vj2)/2 + Pj/ 1000 572= (Vj2)/2 + Pj/ 1000 That's what I can come up with. But I still can't understand what I should do with it and where the pressures in the exits of the tube will be...

Homework Statement So, I need to find the X and Y components of the force in the T section Homework Equations Due the fact that the problem dosn't ask for a specific force I couldn't think in any other equation to use, because even tough there is Pressure and Gravity acting I need to...

Yes I did! Thanks everyone for the help.

Hello everyone! Sorry for the silly mistake and thank you for the quick answers! I'll try my best to not let any algebraic errors pass. So, now I have (x+x2)(3.4-x+11.56-6.8x+x2)-18.5856=0 f(x) = (x+x2)(x2-7.8x+14.96)-18.5856 f(x) = (x+x2)(x+3.8676)2)-18.5856 f'(x) =...

It just seems really odd to me, because in all the other exercises in this list there was a maximum of 4 instances of x in a equation iteration, and this one has 11. I was wondering if I wasn't missing anything.

Homework Statement I'll try to be as clear as possible but this exercise is in portuguese and this is a free translation from me "The sum of two numbers is 3.4 .If we take each of them and summed with they square, the product of it would be 18.5856. The lowest of those number is in the interval...

Hello Everyone! So, I need to calculate the voltage in the capacitor, let's call it Vc(t). For t=0- I know that there is no current in the capacitor. Did some calculations and I've found that Vc(0)=6v. Now i need to know Vc(infinite) But when the switch key is opened and the time goes to...

Hello everyone, So, i have a big test tomorrow and my professor said i should study the DC level in Fourier transform , in the frequency domain. So, i did a little research and found out that the dc level is the percentage of the time a signal is active, and that's all. Can't see how that's...

0*z1+1*z2+0*z3=0 z2=0 <x,z>=0 z1+z3=0 z2=-z3 z is all vectors in the form (x,0,-x)

That's it then! Thank you very much.

<[0,1,0],[z1,z2,z3]>=0 Can i assume that the inner product is <x,y>=x1*y1+x2*y2+x3*y3 because it's a Euclidean Space?

(Thank you for all your help s far) What if i told you that |a-b+b-c| = |a-b| + |b-c|? I'm having a little trouble prooving that but I'm pretty confident.

But in that case g and f are > 0, so in no way will reduce the fraction. |g|+|f|>|g+f| only if g or f is <0

Hi Guys, that's what i got <x,z>=<y,z> <x,z>-<y,z>=0 <x,z>+<-y,z>=0 <x-y,z>=0 x-y = [0,2,0] <2*[0,1,0],Z>=0 2<[0,1,0],z> = 0 <[0,1,0],z>=0 So 'im stuck at that. Any ideas?