Recent content by Lunar Guy

1. Integrate on the interval [0, 1]: (x2 - 1)/(x2 + 1) 2. No relevant equations. 3. S x2/(x2 + 1) - [S 1/(x2 + 1)] = S (x2 + 1) - 1/(x2 + 1) - [(arctan x)] = S -1 - [(arctan x)] = -x - arctan x I can plug in the numbers on my own, but I would like to know if what I've done...

(2x^{2}+4x+2)/(x+1) (2(x^{2}+2x+1)/(x+1) 2(x+1)^{2}/(x+1) 2(x+1)

Yes, that is true because: tan[Tan^{-1} (\frac{3}{4}) ] Cancel each other out. Hint, hint... ;)

Okay, let's work inside of the parentheses first: Sin^{-1} -\frac{1}{2} You can look at this as: sin \theta = -\frac{1}{2} \theta = -30° or 330° Convert that into radians, and you get: \frac{11\pi}{6} or -\frac{\pi}{6} In order for you to get sin x = -1/2, draw a graph...

Thanks. I got it. It's 120 degrees Celsius, right?

\DeltaPE + \DeltaKE + \DeltaU = 0?

Bump. Can anyone help me out?

Bump. Can anyone help me out?

[SOLVED] Specific heat capacity (Calorimetry) Homework Statement When a driver brakes an automobile, friction between the brake disks and the brake pads converts part of the car's translational kinetic energy to internal energy. If a 1500 kg automobile traveling at 32 m/s comes to a halt...

Found it. :)

All right! Thanks. :) Problem solved! EDIT: Ermmm... How do I mark it solved?

1. The time required to fill a bucket with water from a certain garden hose is 30.0 s. If you cover part of the hose's nozzle with your thumb so that the speed of the water leaving the nozzle doubles, how long does it take to fill the bucket? 2. Homework Equations : None required. I hope...

[SOLVED] buoyant force 1. A ferry boat is 4.0 m wide and 6.0 m long. When a truck pulls onto it, the boat sinks 4.00 cm (0.04 m) in the water. What is the weight of the truck? 2. F(sub: B) = F(sub: g)[displaced fluid] = m(sub: f)g (magnitude of buoyant force = weight of the fluid...

Does it seem that I got the right answer?

All right, I'll attempt to work off of that. :) Here we go: PEi + KEi +Ui = PEf + KEf + Uf PEi & PEf = 0 KEf = 0 KEi +Ui = Uf KEi = Uf - Ui <--- (∆U) ½mv² = ∆U ½(2.5 kg)(5.7 m/s)² = ∆U 42 J = ∆U 3.3 × 10^5 J/1.0 kg = 42 J/m m(3.3 × 10^5 J) = (42 J)(1.0 kg) m...