Very simple Simplification Question

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The discussion focuses on simplifying the expression (2x^2 + 4x + 2)/(x + 1) to find l. The user successfully reduces the equation to 2(x^2 + 2x + 1) but struggles to see how to reach the final answer of 2(x + 1). Through guidance, they recognize that (x^2 + 2x + 1) is a perfect square, simplifying to (x + 1)^2. Ultimately, the expression simplifies to 2(x + 1). The thread highlights the importance of recognizing perfect squares in algebraic simplification.
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Homework Statement



(2x^2+4x+2)/x+1 = l

Simplify the equation for l. I do not want to solve it, just simplify.

Homework Equations





The Attempt at a Solution



I actually reduced the equation this far already, and the back of the book says I have gotten the equation right up to this point, but then it gives the answer, but not the steps to get there. The ANSWER: 2(x+1) ... I do not understand how to get that .
 
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(2x^2+4x+2)=2(x^2+2x+1)

can you simplify (x^2+2x+1) further? (think of perfect squares)
 
OH! Ok, I got it. Thanks for the help! I can't believe I missed that.
 
(2x^{2}+4x+2)/(x+1)

(2(x^{2}+2x+1)/(x+1)

2(x+1)^{2}/(x+1)

2(x+1)
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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