Recent content by meanyack

At first glance, it seems easy. But when you try to find the angle between vector C and plane consisting A and B, then it seems complicated. So is there any way to calculate it easily?

Homework Statement Please find the attachment for vectors. If I know \alpha, \beta & \theta (colored angles) how can I find the angle between vectors C and D in terms of \alpha, \beta & \theta ? Homework Equations Cross product & dot product The Attempt at a Solution

Problem isn't drivers. I have the necessary drivers. The problem is how I can make a setup and make a .vi file.

Hi to all, For a project I need to measure output (as Volts) of a circuit. I want to do this with a SRS830 lock-in by using Labview application. Google search gave me nothing. If anyone knows how to set this up, please help. Thanks

Homework Statement Here is the question: how can we know that if we have discrete or continuous spectrum just by looking at the potential graph? Specifically, let`s consider the potential V(x)=-F*x (F:const) . After we solve, we can conclude wavefunctin is airy function, and so both...

As Dick said, firstly let u=\frac{x-x_{0}}{a} then du= adx and now integral becomes \frac{1}{a^{5}}\int^{\infty}_{-\infty}\frac{1}{1+u^{4}}du Secondly, by letting u=e^{i\theta} and du=i*{e}^{i\theta}d\theta you can use "residue theorem". Yet, I forgot...

I forgot to say that you must normalize this function ie \int_{a}^{b}\left|P(x)\right|^{2}*dx=1 if the interval is not given you'll probably use [-\infty,\infty]. So that you can determine the constant "A".

use this integration \int_{a}^{b}\left|P(x)\right|^{2}*x*dx in the given interval [a,b] At least, we're doing so in quantum meachanics

Hey guys, our instructor posted the answer to the question. I never thought spliting the problem like in answer... The method is quite impressive. If you wonder, here is the link http://www.fen.bilkent.edu.tr/%7Ebulutay/315/hw3_s1.gif http://www.fen.bilkent.edu.tr/%7Ebulutay/315/hw3_s2.gif

Actually, I was wondering that. This can help me... thanks

The boundary conditions are on the picture Let me write them again v(x=0,y)=0 v(x,y=0)=0 v(x,y=a)=0 while x goes to inf, V(x,y)=Y(y) Edit: You said " You cannot combine the two solutions and expect the same result as if you had done it properly the first time." but, yes we can...

Did you mean Fourier transform or Fourier series expansion? You know, they are different

If you don't seperate, you can't find the constant k=n*pi/(2*a) because, in original shape boundaries are different so you can't choose a cyclic function ie f(x)=f(x+T). Actually, it's not an easy question, because you will be stuck when you look try to solve first part. To understand, give...

Homework Statement To see the problem, please click the link below: potential_problem.jpg Homework Equations \nabla^{}2V=0 Seperation of variables: V(x,y)=X(x)Y(y) The Attempt at a Solution For simplicity I divide problem into two parts: 1st part- Click the link below...

why can't I see a button "delete topic" because this is the wrong topic, the original one is the other one