Trying to figure out integral with infitnite limites

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Homework Help Overview

The discussion revolves around evaluating the integral \(\int^{\infty}_{-\infty}(1/(a^{4}+(x-x_{0})^{4}))dx\), which involves infinite limits and requires techniques from calculus and complex analysis.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore different substitutions, such as letting \(u = (x-x_{0})/a\) and \(u = (x-x_{0})^{4}\). There are mentions of factoring and using partial fractions, as well as the potential application of the residue theorem.

Discussion Status

Some participants have provided guidance on substitutions and methods, while others express uncertainty about applying certain techniques. There is acknowledgment of the complexity of the integral, and multiple approaches are being considered without a clear consensus on the best path forward.

Contextual Notes

Participants note the importance of returning to the original variable \(a\) in their final expressions and the challenges posed by the integral's complexity.

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Homework Statement



[tex]\int^{\infty}_{-\infty}(1/(a^{4}+(x-x_{0})^{4}))dx[/tex]

Homework Equations


The Attempt at a Solution



i let [tex]u = (x-x_{0})^{4}[/tex]

but have no idea what to go from there
 
Last edited:
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I would use u=(x-x0)/a and factor out the a^4. That gives you 1/(1+u^4). (1+u^4)=(u^2-sqrt(2)u+1)*(u^2+sqrt(2)u+1). Use partial fractions on that. It's not an easy integral, but it can be done.
 
awesome thanks! got [tex]\pi*\sqrt{2}/2[/tex]
 
z00maffect said:
awesome thanks! got [tex]\pi*\sqrt{2}/2[/tex]

Good job. Don't forget to put the 'a' factor back in again.
 
As Dick said, firstly let [tex] u=\frac{x-x_{0}}{a}[/tex] then [tex]du= adx[/tex] and now integral becomes

[tex] \frac{1}{a^{5}}\int^{\infty}_{-\infty}\frac{1}{1+u^{4}}du[/tex]
Secondly, by letting [tex]u=e^{i\theta}[/tex] and [tex]du=i*{e}^{i\theta}d\theta[/tex]
you can use "residue theorem". Yet, I forgot how can we apply here. After I remember, I'll post it
 

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