If you directly ask ChatGPT if it can play chess, is says no, so you type something like this...
"Lets play blindfold chess, I play white and you play black, I make the first move. Pawn to e4, you next".
Then it responds with e5, then I thought I need to open another tab with an engine to see...
In the graph class definition, this method was returning wrong edges.
getEdgesFromNode(node) {
let edges = []
if(this.adjacencyList[node]) {
for (let i = 0; i < this.adjacencyList[node].length; i++) {
if(this.adjacencyList[node][i].direction.from === node) { // this...
This is the weighted, directed acyclic graph I created in JavaScript
class WeightedDirectedGraph {
constructor() {
this.adjacencyList = {};
}
addNode(node) {
if(!this.adjacencyList[node]) {
this.adjacencyList[node] = [];
}
}
addEdge(node1, node2, direction, weight) {...
So half of ##\Delta y## of the string moves towards the pulley B from under it and the other half moves away, over it, summing up to ##\Delta y## length of string moving towards right, so the distance moved by the pulley is ##\frac {\Delta y}{2}## is this how you see it ?
Ignoring the pulley radius.
##{x_0}## and ##{x_1}## are distances from mass 2M to pulley B, they are constants.
##{y_0}## and ##{y_1}## are the distances of mass M from pulley A.
##{l_0}## and ##{l_1}## are the distances between the pulleys A and B with respect to positions ##{x_0}## and...
I solved this problem by assuming that the acceleration ##a## is the same on the both the masses M and 2M but then answers were wrong, but if the acceleration of the mass 2M is considered as ##a/2## then I get the right answers, but I don't how exactly acceleration is getting halved for mass 2M...
I think so too, Putin didn't just wake up one day and decide to invade Ukraine. His discontent over Ukraine's eagerness to join the EU and/or NATO, continued expansion of NATO eastwards... Ukraine was the last straw. He has been planning this for several years perhaps. I think people...
The free body diagram of one pulley should look like above, the other one will be a mirror image.
The tension ## T_2 ## is created by the man's friends pulling the rope.
## T_1 ## has a vertical and a horizontal component. The vertical component (downwards) is balanced by the normal reaction of...
The diagram represents one half of the system.
##W## is the weight of the man.
##T_1 cos \theta = T_2## --> The horizontal component of ##T_1 = T_2## right ?
##T_1 cos \theta = T_1 \frac {d}{\sqrt {4h^2 + d^2}} = T_2##
##T_1 sin \theta = \frac {W}{2}##...