Recent content by Monsterboy
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ChatGPT Examples, Good and Bad
If you directly ask ChatGPT if it can play chess, is says no, so you type something like this... "Lets play blindfold chess, I play white and you play black, I make the first move. Pawn to e4, you next". Then it responds with e5, then I thought I need to open another tab with an engine to see...- Monsterboy
- Post #73
- Forum: Computing and Technology
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Comp Sci Using Single Source Shortest Path Algorithm to find the longest path
In the graph class definition, this method was returning wrong edges. getEdgesFromNode(node) { let edges = [] if(this.adjacencyList[node]) { for (let i = 0; i < this.adjacencyList[node].length; i++) { if(this.adjacencyList[node][i].direction.from === node) { // this...- Monsterboy
- Post #4
- Forum: Engineering and Comp Sci Homework Help
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Comp Sci Using Single Source Shortest Path Algorithm to find the longest path
Is the idea of multiplying the edge weights by -1 to find the longest path right ? Does it actually work ?- Monsterboy
- Post #3
- Forum: Engineering and Comp Sci Homework Help
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Comp Sci Using Single Source Shortest Path Algorithm to find the longest path
This is the weighted, directed acyclic graph I created in JavaScript class WeightedDirectedGraph { constructor() { this.adjacencyList = {}; } addNode(node) { if(!this.adjacencyList[node]) { this.adjacencyList[node] = []; } } addEdge(node1, node2, direction, weight) {...- Monsterboy
- Thread
- Algorithm Algorithms Computer science Graphs Path Source
- Replies: 4
- Forum: Engineering and Comp Sci Homework Help
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Find the acceleration of the masses
So half of ##\Delta y## of the string moves towards the pulley B from under it and the other half moves away, over it, summing up to ##\Delta y## length of string moving towards right, so the distance moved by the pulley is ##\frac {\Delta y}{2}## is this how you see it ?- Monsterboy
- Post #10
- Forum: Introductory Physics Homework Help
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Find the acceleration of the masses
Some people told me that but I am not able to visualize the distance moved by the pulley B to be exactly equal to ##\frac {\Delta y}{2}##- Monsterboy
- Post #7
- Forum: Introductory Physics Homework Help
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Find the acceleration of the masses
Ignoring the pulley radius. ##{x_0}## and ##{x_1}## are distances from mass 2M to pulley B, they are constants. ##{y_0}## and ##{y_1}## are the distances of mass M from pulley A. ##{l_0}## and ##{l_1}## are the distances between the pulleys A and B with respect to positions ##{x_0}## and...- Monsterboy
- Post #5
- Forum: Introductory Physics Homework Help
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Find the acceleration of the masses
I solved this problem by assuming that the acceleration ##a## is the same on the both the masses M and 2M but then answers were wrong, but if the acceleration of the mass 2M is considered as ##a/2## then I get the right answers, but I don't how exactly acceleration is getting halved for mass 2M...- Monsterboy
- Thread
- Acceleration
- Replies: 12
- Forum: Introductory Physics Homework Help
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Navigating the Tensions in Ukraine: A Scientific Perspective
I imagine this will be Afghanistan 2.0. I only hope the Ukranians don't end up with their own version of the Taliban after this is over.- Monsterboy
- Post #672
- Forum: General Discussion
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Navigating the Tensions in Ukraine: A Scientific Perspective
I think so too, Putin didn't just wake up one day and decide to invade Ukraine. His discontent over Ukraine's eagerness to join the EU and/or NATO, continued expansion of NATO eastwards... Ukraine was the last straw. He has been planning this for several years perhaps. I think people...- Monsterboy
- Post #604
- Forum: General Discussion
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Tension on both sides of the rope is supposed to be the same?
I got the answer for the tension.- Monsterboy
- Post #11
- Forum: Introductory Physics Homework Help
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Tension on both sides of the rope is supposed to be the same?
The free body diagram of one pulley should look like above, the other one will be a mirror image. The tension ## T_2 ## is created by the man's friends pulling the rope. ## T_1 ## has a vertical and a horizontal component. The vertical component (downwards) is balanced by the normal reaction of...- Monsterboy
- Post #7
- Forum: Introductory Physics Homework Help
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Tension on both sides of the rope is supposed to be the same?
The pulley is fixed in its position. Lnewqban's image is accurate.- Monsterboy
- Post #5
- Forum: Introductory Physics Homework Help
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Tension on both sides of the rope is supposed to be the same?
The diagram represents one half of the system. ##W## is the weight of the man. ##T_1 cos \theta = T_2## --> The horizontal component of ##T_1 = T_2## right ? ##T_1 cos \theta = T_1 \frac {d}{\sqrt {4h^2 + d^2}} = T_2## ##T_1 sin \theta = \frac {W}{2}##...- Monsterboy
- Thread
- Rope Tension
- Replies: 11
- Forum: Introductory Physics Homework Help
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Distance moved in two different inertial frames
Aren't the frames of the stationary elevator and the ground basically the same ? Ok, this is what I wanted to know.- Monsterboy
- Post #10
- Forum: Introductory Physics Homework Help