Ahah. Thank you for your help.
What about for the Hamiltonian
H = \sum_k \left(\epsilon_k - \mu\right) c^{\dag}_k c_k + \gamma \sum_{kp} c_k^{\dag}c_p
Can I use the same method to determine the ground state? What does this Hamiltonian represent?
Nope, I was just given that Hamiltonian and told to find the ground state, the energy of the ground state E_0 and the derivate wrt \mu, so if E_0 = \epsilon_k - \mu then \frac{\partial E_0}{\partial \mu} = -1. (and if E_0 = 0, then obviously the derivate is zero).
Is this a 'famous' result?
Okay, so the matrix representation of these operators is
c^{\dag}c = \left(\begin{array}{cc}0 & 1 \\ 0 & 0\end{array}\right)\left(\begin{array}{cc}0 & 0 \\ 1 & 0\end{array}\right) = \left(\begin{array}{cc}1 & 0 \\ 0 & 0\end{array}\right)
And the Hamiltonian of the kth term will be
H_k =...
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I have been given the Hamiltonian
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