Recent content by Mr. Snookums

If it has velocity and mass, doesn't it have kinetic energy?

Find the force pulling the skier down the hill. This is the force required to pull him up. That is a good place to start. From there, remember that KE=(1/2)mv^2 and also that W=Fd.

Lithium-6 ions (mass is 6x a proton mass) are charged Li+ ions (one extra proton). They are accelerated by 2000 volts and passed through a velocity selector with a magnetic field of 0.020T into the page. The ions follow a straight path through the selector and are then deflected onto a piece of...

I know how to solve a regular question such as x^x, but how would I find: lim[1-(4/x)]^x x->inf My study guide says that I have to use Ln and then L'Hopital's Rule, and I can see how that would work, but what happens to the limit?

Ah, yes. I had forgotten all about solving these buggers with logarithms. Thank you.

(x^2+1)^(x^3) I'm not sure how to do this. Any tips? How would I treat the power? Should be x^3 as the power, not 3x.

Ah, I see. Separating the second integral isn't needed because I can do it with substitution. Thank you.

\int{\frac{x^3+x^2+x-1}{x^2+2x+2}dx} I divided the polynomails and got: \int{(x-1)dx}+\int{\frac{x+1}{x^2+2x+2}dx} This becomes: x^2-x+\int{\frac{x}{x^+2x+2}dx}+\arctan{(x+2)} If I've done this right, how do I integrate the third term? The arctan should have the (x+2) in brackets but I'm...

So now I just plug 1/16 in for f''(xo) and make M greater than it? What about x? M>x^2/32. Is x any number in the interval [-2,2]?

Thank you for answering. Is it assumed that when we see M in this type of question that it is the upper bound? From where do we get abs(5+3x-f(x))? My teacher told me it was a Taylor series problem, so the error would be: abs((1/2)(yo'')(x-xo)^2) Am I on the right track?

I'm in AP Calculuc and was given a homework package, which is an old university introductory calculus exam. There is one particular question with which I'm having a terrible time. It is known that f(0)=5 and the tangent line to the graph of f(x) at (0,5) is y=5+3x. It is also known that...

Find the volume formed by rotating the area contained by y=sqrt(6x+4), the y-axis and the line y=2x about the y-axis. Set up, but do not evaluate the integral. First I graphed it, then did the "washer" method of finding the area of the circle formed, and found that the radius is...

I understand that, but why would we use both vertical and horizontal components in the same torque equation?

A ladder is against a frictionless wall, elevated at angle theta above the ground. I have a question about distance components. We find the torque pushing the ladder to the ground by using horizontal distance components: the distances of the weights acting on the ladder multiplied each by...

It is a vector because it has direction.