Recent content by mrnastytime

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    How Does a Hydraulic Lift Work with Different Piston Sizes and Weights?

    Homework Statement A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 460 cm2. It is filled with oil of density 560 kg/m3. Homework Equations a)What mass must be placed on the small piston to support a car of mass 1100 kg at equal fluid levels? A:35.86 kg...
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    Simple Pendulum Period Calculation for Different Conditions

    What is I?...if the length is doubled, shouldn't the time increase? but how would i interpret that on paper with the given equation?
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    Simple Pendulum Period Calculation for Different Conditions

    Homework Statement A pendulum has a period of 1.8 s. Homework Equations Its length is doubled. What is its period now? The original pendulum is taken to a planet where g = 16 m/s2. What is its period on that planet? The Attempt at a Solution T=2pi sqrt(L/g) 1.8=2pi...
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    Solving the Physics of a Rolling Loop-the-Loop

    hey I am working on the same problem as you remember: v=sqrt[g(R-r)]/2 = omega plug this into MGH = 1/2 M V^2 (1 +(I/mr^2)) You can figure out the rest. However i am stuck on (a), what is the total kinetic energy of the ball (translational plus rotational) at the top of the loop?
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    Angular Acceleration of Rod w/ Pivoted Weight

    im having trouble redoing the calculation for the change in height. is the sin 53 part correct? because if you want the rod to be vertical, the tip of the rod with the weight will be pointing down, thus 90-37=53 degrees?
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    Angular Acceleration of Rod w/ Pivoted Weight

    The part of the rod that's attached to the weight. The change in height is the point from which theta=37 degrees to the height when the rod is vertical at 90 degrees. The potential energy of the rod does not change because the pivot point is the center of mass?
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    Angular Acceleration of Rod w/ Pivoted Weight

    I=moment of inertia of rod-weight system=61.50 m=10.1 kg h=change in height of the rod from 37 degrees to 90 degrees
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    Angular Acceleration of Rod w/ Pivoted Weight

    sorry i don't quite understand what you're asking, I=moment of inertia m=mass w=omega the potential energy is mgh and kinetic energy is .5Iw^2
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    Angular Acceleration of Rod w/ Pivoted Weight

    Homework Statement A uniform rod is pivoted at its center and a small weight of mass M = 5.07 kg is rigidly attached to one end. You may neglect the size of the weight and assume it is located right at the end of the rod. Homework Equations Now suppose that the rod has length L = 5.4 m...
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    What is the new distance between the man and the shore after he switched seats?

    Homework Statement A man decides to boat out on the lake for a relaxing day of fishing. At one point during the day, he finds himself facing the shore. He judges that he is a distance Dinit = 35 ft from the shore. The man has a mass of Mman = 190 lbs, and the boat a mass of Mboat = 270 lbs. The...
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    Energy Conservation: Block & Spring

    thank you, i figured it out.
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    Energy Conservation: Block & Spring

    Homework Statement An object of mass M = 4 kg slides from rest a distance d = 4 m down a frictionless inclined plane where it encounters a spring. It compresses the spring a distance D = 1 m before stopping. The inclined plane makes an angle q = 20° with the horizontal. Homework Equations...
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    Calculating Work on Incline: Solving for Gravitational Force Work

    Homework Statement A horizontal force of magnitude F = 197 N is used to push a box of mass m = 5 kg from rest a distance d = 13 m up a frictionless incline with a slope q = 34°. Homework Equations How much work is done on the box by the gravitational force during this same displacement...
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