Recent content by negat1ve

Not really a problem but a concept I am having trouble understanding and I was hoping someone can explain to me better. We performed an experiment in lab last week on finding the Young's modulus of copper by projecting a laser on the wall to magnify the effect of the change in length of the...

Oh ok I get it now. Thanks!

Homework Statement Use the same device to separate singly charged CO2 having 12C and 14C. What are the radii of curvature? This is a follow up question based on a HW problem I answered last week. The original problem was this: A doubly charged helium atom is accelerated by a voltage 2700V...

It's not a problem buddy it was a question. Thanks for your response but I figured it out already on my own.

Will a current carrying wire stretched between two supports deflect in different directions when current is goes through the wire in one direction and then reversed?

ok, i solved this, thanks!

sorry, can anyone walk me through this problem or hint at some steps i need to do this. why can't i simply use the equation f= I l b sin(theta) using the angles i found the wire to be. Is when the mag field is given as B=(.318i)T mean that it is only in the x direction? Thats what i am...

Sorry, it was a 63 degree angle I had.

Homework Statement A stiff wire 50 cm (0.5 m) long is bent at a right angle in the middle. One section loes along the z axis and the other is along the line y=2x in the xy plane. A current of 20A flows in the wire -down the z-axis and out the line in the xy plane. The wire passes through a...

For a lab yesterday we recorded points to plot the I-V graphs for a few resistors and a light bulb. The light bulb was supposed to show that some that some devices don't obey ohms law but when plotting the graph I am cutting more of a straight line then a curve showing that it DOES! Could this...

wow I am an idiot haha that makes so much sense and is so much easier than thinking about it the way i was. thanks for the help!

My new equivalent capacitance is Ceq = C1 + C2 = C10 + K*C20 So the total capacitance has increased. And Ceq = Qeq / Veq where Qeq = Q1 + Q2 stays the same so Veq = V1 = V2 has to decrease to balance out the equation. I want to say that Q1 = CV = C10*V0/k = Q10/k So for Qeq...

I said that the dielectric is added to C2. So the new capacitance for C2 is C2 = KC20 and C1 is still C1 = C10 Using the voltage drop result from my textbook, if i apply this i get that V2 = V1 = V0/K I also know that the equivalent charge Qeq of the initial setup with the battery connected...

Homework Statement Two identical capacitors are connected in parallel. Each acquires a charge Q0 when connected to source voltage V0. The voltage source is the dissconnected and a dielectric(K=3.2) is inserted to one of the capacitors. Determine the charge on each and voltage across each...

Homework Statement Show that the two inputs given by x = Asin(wt) and y = Acos(wt) would display a circle of radius A on the display of an oscilloscope? 2*pi*f = w This is a bonus lab question i am supposed to look online and research how to do but can't find anything that explains it...