Recent content by nickb145

Alright, I know how to find the integral of a regular function, But an inverse, is throwing me off Can someone explain why 1/Sqrt(7t)dt is 2sqrt(t/7) I'm probably missing something, but why does the variable end up as a numerator? I know the inverse is 1/(r+1)x^(r+1) So I work it out as...

But it is strange that i get a higher frequency of what it should be. The answer is 381.4 and i keep getting 479. I'm getting my signs wrong somewhere... I used f'=f/(1+Vs/V) for a source moving away from reciever.

vy=Vyi-gt right? initial speed is 0 so its just -9.8*4=-39.2

thinking

Homework Statement A parachutist leaps from a hovering helicopter, after 4.0s of freefall shouts back at 425Hz. What frequeny is heard at the helicopter? Homework Equations f'=f/(1+Vs/V)Vsource=? f'=? f=425Hz V=343m/s The Attempt at a SolutionI'm stuck on finding the speed for the jumper...

Never mind i figured it out. Thank you very much for the assistance!

Now for the energy before the bullet strikes. Before the bullet enters the wood block i just have the kinetic energy of the bullet. Because i assume the spring is at x=0 and that just cancels out the potential energy. Now for after the collision I used the X=Acos(ωt) to get X. I got .2544...

So now the Amplitude is .256m using Vmax=sqrt(k/m)A

1.73m/s?

Interesting. SO i just take the difference between Vmax and Vmin? Vmax 485=Sqrt(79/.0062)A A=4.296 Vmin 1.731=-sqrt(79/1.7362)A= -.256 Which i now have is 4.039m. Which mastering physics tells me is incorrect.

I think using the conservation of momentum will work. M1V1 + M2V2 = (M1 + M2)V3 .0062(485)+1.73(0)=(1.7362)V3 V=1.73m/s (that is a massive drop)

I'm not really sure. I used it because i assume that 485 IS the max velocity

Homework Statement A 6.20g bullet traveling at 485m/s embeds itself in a 1.73kg wooden block at rest on a frictionless surface. The block is attached to a spring with k = 79.0N/m A)Find the Period B)Find the Amplitude C)Find the totla energy of the bullet+block+spring system before the...

Ok so the ideal gas equation is PV=NkbT Since i see pressure there i divided the volume so i can get P=(NkbT)/v I set the 2 equations equal to each other and simplified to get T=(mv2)/Kb if that makes any sense.

Homework Statement An ideal gas has rms speed vrms at a temperature of 288K . At what temperature is the rms speed tripled? Homework Equations P=(NmV2)/3V The Attempt at a Solution I'm kind of stumped on this one. Other ones I've done are pretty simple to figure out, but the...