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**Alright, I know how to find the integral of a regular function, But an inverse, is throwing me off**

Can someone explain why 1/Sqrt(7t)dt is 2sqrt(t/7)

I'm probably missing something, but why does the variable end up as a numerator?

I know the inverse is 1/(r+1)x^(r+1)

So I work it out as

1/(-.5+1) which goes out to 2

then the rest

(7t)^-1/2+1

(7t)^1/2

(what am I missing here)

=2sqrt(t/7)+C