Recent content by Numzie

Homework Statement Loop with radius 22m is all that is given and the required velocity to complete this loop is asked for. Homework Equations What I'm looking for. The Attempt at a Solution I've tried many equations, the answer is 33m/s but I don't know what equations to use to...

Oh, I see what I did wrong then. I subtracted the total wavelength of both first then divided by 2 instead of using the tube length. Thanks for all the help!

So then 343.5/262.53=1.30842m Wavelength. 1.30842m-1.29m=.01842m =18.42cm 18.42/2=9.21cm Same as what i got first time around since frequency can not be negative.

Velocity of sound is affected by temperature. V_Sound{} = 331.5\times.6(Temp\degree{}C)

It seems as if no one could be bothered with problems involving waves and that everyone sticks to the other problems instead. Neither of my two requests for help involving waves have been seen too :(

Need urgent help, beat frequencies and tuning. Homework Statement http://img144.imageshack.us/img144/4337/2aee8.th.jpg Homework Equations The Attempt at a Solution You can see my attempt in the picture. I assume that beat frequencies are the absolute value of the difference...

I'm sure you've hear or seen this. Its a device that has two bowl shaped mirrors on top of each other, facing each other and the top bowl has a hole cut in the top. The device creates a mirage of any object placed at the bottom that seems to levitate above the hole. How can this phenomena be...

Thats true, my bad.

K being Kelvin? And I don't exactly understand your question, do you need to prove that 1C is not equal to 1Kelvin? Because its not. 1C = 274.15Kelvin

Well I'm not 100% certain its that but I just used logic. Division is the inverse of multiplication so if f[g(x)]=R(x) then f(x)=R(x)/g(x). i.e. f[g(2)]=12 then f(x)=12/2. 12/2=6 and 6(2)=12

This because 0/0=1 but 0(0)=0?

So 0/0 can be proven to be defined but the definition states that it must be undefined?

f(x)=R(x)/g(x)

I've searched all over for something but can't find anything. From what I can reason there would be a limit for two reasons: 1) Because the human ear can only hear a limited about of frequencies.(I assume this is correct but doesn't really relate to the given situation) 2) Frequency and...

Is there a theoretical limit to the lowest note achievable in a closed tube(Pop bottle)? Heres the question in context: I've got what I believe to be the correct: http://img141.imageshack.us/img141/9301/1azw1.jpg ^^ May want to check that, if you don't mind ^^