For the units to work out I HAVE to know r0. Maybe my value is crap, but at least my solution shows the understanding is there. It turned out to not be too hard...maybe a little convoluted. Thanks for the help!
So I took r0 to be the ion separation between na and cl which was 0.28 nm. Using this and all of the other information, I ended up with a frequency of 1.19*10^13 hertz. Is this reasonable?
Well, I end up with the spring constant being \frac{k\alpha e^{2} \left(m-1\right)}{r_{0}^{3}} and plugging this into mathematica shows the tangent, which is in good agreement for small deviations. Great...so now what?
I did this! So I converted r to r_{\circ}+\Delta r and get F=-k\alpha \frac{e^{2}}{r_{\circ}+\Delta r}[1-\left(1-\frac{\Delta r}{r_{\circ}}\right)^{1-m}] and say that \frac{\Delta r}{r_{\circ}} is much less than 1 (which is reasonable for small angles). I was hoping that this would get rid of...
Homework Statement
The force between an ion pair is given by F=-k\alpha\frac{e^{2}}{r^{2}}[1-\left(\frac{r_{\circ}}{r}\right)^{m-1}]
Find the value of r where the equilibrium position is.
Determine the effective spring constant for small oscillations from the equilibrium.
Using...
Thanks for looking over it. One concern was that the height doesn't factor into this ratio. That seems a little strange to me, but I can accept it as true. This isn't necessarily a difficult problem, but it was difficult to keep track of the variables as there are essentially three stages to the...
Now I'm confused again :confused:
Okay, step by step. Follow along and tell me where my mistake is. Momentum is conserved. Kinetic energy is not.
Step 1: The potential energy of the car an Earth turns completely into kinetic energy of the car (ignoring kinetic energy of the earth).
Step...
So is it okay to consider the kinetic energy of the first car before and after the collision and the kinetic energy of the second car before and after the collision separately like I did?
Homework Statement
Starting from rest, a railroad car rolls down a hill 20 m high and hits another identical car at rest. The cars lock together after the collision. What fraction of the first car's change in potential energy is converted into thermal energy in the collision?Homework Equations...
That's really neat and useful. I was so accustomed to just glazing over (1-Sqrt[5])/2, that I forgot that it was negative. If you raise it to the power of 1/2 for example, then the answer is imaginary. That's why it is not a real-valued function, correct? Thank you, sir.
Ouch. I do not claim to be awesome. I have no idea what I am doing here and I need help from people who do (and who are thereby more awesome than I am). My question is where to start. If I had a good idea about what I wanted to ask, then I wouldn't need suggestions. What things do I need to be...
Right now I am on track to be a math and physics double major, but I just finished my freshman year, so I haven't declared yet (all male liberal arts college). I won't know my GPA until May 15th and since it is freshman year, it doesn't matter a whole lot. I may have a 4.0 (on a 4 point scale)...