The answer is apparently:
B =(0.8)^(1.5)*(u*N*I/R)
Could you please explain to me how this comes to be the conclusion...? I'd at least like to understand this problem... :(
Thank you! I looked up the general equation for the magnetic field along the axis of a finite solenoid, and found something:
http://www.netdenizen.com/emagnet/solenoids/solenoidonaxis.htm
However, it seems I must know the inner radius...I will assume it is zero and see what happens. I also...
Homework Statement
A glass cylinder of radius R, length l, and density \rho has a 10-turn coil of wire wrapped lengthwise, as seen in the figure . The cylinder is placed on a ramp tilted at angle \theta with the edge of the coil parallel to the ramp. A uniform magnetic field of strength B...
Homework Statement
Two identical coils are parallel to each other on the same axis. They are separated by a distance equal to their radius R. They each have N turns and carry equal currents I in the same direction.
Find an expression for the magnetic field strength at the midpoint...
The homework website says my answer of 0.078 V/m is wrong. I'm utterly confused. I'll have to address my professor about this problem, as well as the other problem. I've double checked every single possible error for units, etc. as well.
HAHA...sorry, but did you take a look at the thumbnail..? It's all there. Same current is flowing through both wires, and aluminum has a diameter of 1.0 mm. All good?
I'd at least like to know if the equation(s) I ended up with were wrong or not, or if I'm not including something in my...
Really? All I did was "Equate the two current equations"...
So here it is:
σEA = σEA
The left side representing Nichrome, and then the right side representing aluminum. Then I solved for the E-field of the unknown wire getting:
E = (σEA)/(σA)
The top part of the fraction being...
Homework Statement
What diameter should the nichrome wire in the figure be in order for the electric field strength to be the same in both wires?
Homework Equations
σ = 1/ρ
J = σ*E...I/A = σ*E...I = σ*E*A
Then, equate the current equations for each wire.
The Attempt at a...
Homework Statement
For what electric field strength would the current in a 2.0 mm diameter nichrome wire be the same as the current in a 1.0 mm diameter aluminum wire in which the electric field strength is 0.0080 V/m?
aluminum diameter = 1.0 mm
Same current(I) flowing through both wires...
ohhh...well, I overthunk it. Lol! So, take the velocity I found, and divide it into the circumference: (2*pi*r)/v = seconds...in other words the period. THANKS! It worked!
Homework Statement
In a classical model of the hydrogen atom, the electron moves around the proton in a circular orbit of radius 0.053 nm.
What is the electron's orbital frequency?
What is the effective current of the electron?
Homework Equations
Freq * Wavelength = Speed of...
Wow...I got it! The inner charge has to be opposite the inner charge, and I was able to solve for the two points by utilizing gaussian surfaces to give me the charges of the exterior surface of both! Your help is greatly appreciated!
WOO!
Hmm...then it would seem to me that the point outside both the spheres would be easiest to calculate! By what you've said...do you mean that the inner surface of the Hallow sphere is actually inducing no E-field at that point..?
I think I am only confused now about the Inner E-field, I will...
Ah, I think I'm understanding this now...I do know that the meat a conductor has an E-field of zero (E = 0). So, since the net charge only stays apparent on the exterior surface...would the interior surface charge stay the same? -65nC, in order to block the E-field of the +65nC point Charge...
In the attached picture is all of the information to complete this problem. The picture is of a solid sphere at the center of a hallow sphere, both of which are conductors.
The question asks to find the total charge of the exterior and interior surfaces of the hollow conductor, as well as the...