Recent content by rickz02

Can you elaborate here using the PF format. Also show us first what you've done so far. Thanks.

@Ab17 double check your computation in (a).

To compute for the displacement of point C use the equation for free falling bodies. As for point P, compute for the angle using the angular velocity and you will find that it has traveled all the way to the other side of the sphere (be careful here as you are dealing with displacement, not...

Take note that a stationary object has traveled a distance equal to Earth's radius in 24 hours (assuming Earth is a perfect sphere).

Have you considered adding y-intercept to your equation? I plotted your data and obtained the linear equation F_c = 177\sqrt[4]{F}-165 . Also, I think the slope you have (3/0.02) is too underestimated for your data points.

You have to understand first what is given, is it frequency or period? After that, you can correctly answer the questions.

Seems like \partialslash is not working, but Dirac equation should look like this:

Dirac equation (in natural units) by one of my Physics heroes: (i\partialslash-m)\psi = 0 This is one of the simplest equation in quantum field theory yet the most elegant of all. It's very short but it tells a lot everything there is.

No you can't, this is where you're going to use the dimensions of the mountainside. Also take note that I believe you simply can't do that, you are given with a volumetric density 1900 kg/m3. Obviously the mass would. Aside from the fact you are adding mud, the mountainside is also...

No you can't, this is where you're going to use the dimensions of the mountainside. Also take note that I believe you simply can't do that, you are given with a volumetric density 1900 kg/m3. Obviously the mass would. Aside from the fact you are adding mud, the mountainside is also...

I don't know if the error propagation method you use is satifactory enough but I strongly suggest to use the least squares method. Anyway, to answer (c) you can use the percentage difference criterion. You can also answer it by checking if the accepted value falls within the range of the...

Solve the y displacement instead using the time you got. The time you got is the time at which the ball is at x = 36.0 m, so the next step would be to calculate the height of the ball at that time. Then compare that height to the height of the crossbar and answer question a.

The answer 0.0207 cm^3 doesn't look right to me. Mercury has a higher linear of expansion thus its expansion should be greater than that of the glass. For me 2.07 cm^3 is a more convincing answer. Where did you get that solution anyway?

Hint: To solve for t, use the quadratic eaquation.

Frequency simply means how often (per sec) an occurence happens over a given duration of time. For this case the occurence is the pulse. So the question is how often or how many pulses are observed every second. Just ignore the idea that a pulse is half wave, I'm not sure with that. A pulse...