When Will the Package Hit the Ground?

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SUMMARY

The discussion focuses on calculating the time it takes for a package to hit the ground after being dropped from a hot-air balloon ascending at 10 m/s from a height of 84 m. The relevant physics equation used is Yf = Vo*t + (1/2)*a*t^2, where Yf is the final height (0 m), Vo is the initial velocity (10 m/s), and a is the acceleration due to gravity (-9.8 m/s²). The user is advised to apply the quadratic equation to solve for time, indicating a need for algebraic manipulation to isolate the variable.

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Homework Statement


A hot-air balloon is ascending at the rate of 10 m/s at a height of 84 m above the ground when a package is dropped.

Find time it took to hit the ground

Find Final velocity

Homework Equations


The Attempt at a Solution



Initially, I am inclined to use the equation Yf = volt + (1/2)at^2

I know that a=-9.8 m/s^2
Vo = 10m/s
Yf=84m

With four variables and 3 are known, I can find time.

The part I am having trouble with is setting up the equation where time is a function of velocty and position (where as t=something)

Am I even approaching this problem correctly? Any help will be much appreciated.
ATranPV

EDIT: Yes...my algebra sucks...:(
 
Last edited:
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Hint: To solve for t, use the quadratic eaquation.
 

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