Calculating Centripetal Acceleration at Earth's Equator

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SUMMARY

The centripetal acceleration of an object at Earth's equator is calculated using the formula a = v²/r, where v is the tangential velocity and r is the radius. Given that the radius of Earth at the equator is 6.38 x 106 m, the tangential velocity can be determined by the distance traveled in one rotation (the circumference) divided by the time taken for one rotation (24 hours). This results in a centripetal acceleration of approximately 0.0339 m/s².

PREREQUISITES
  • Understanding of basic physics concepts, specifically centripetal acceleration
  • Familiarity with the formula a = v²/r
  • Knowledge of Earth's radius and rotation period
  • Ability to perform unit conversions (e.g., hours to seconds)
NEXT STEPS
  • Calculate the tangential velocity of an object at Earth's equator
  • Explore the effects of centripetal acceleration on objects in circular motion
  • Investigate variations in centripetal acceleration at different latitudes
  • Learn about the implications of centripetal acceleration in satellite motion
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the effects of Earth's rotation on objects at the equator.

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Homework Statement


the centripetal acceleration of an object at Earth's equator results from the daily rotation of Earth. Calculate the object's centripetal acceleration, given that the radius of Earth at the equator is 6.38*10^6m.

Homework Equations


a=v^2/r

The Attempt at a Solution


I really have no idea how to solve this question, how can I calculate the centripetal acceleration with only the radius?
 
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Take note that a stationary object has traveled a distance equal to Earth's radius in 24 hours (assuming Earth is a perfect sphere).
 
Last edited:

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