Recent content by S_fabris

ahhh ok i see what i did wrong! Perfect thank you very much for your time! Sergio :D

Hey we finally got the answer...for the pressure...do not add the atmospheric pressure...simply use the one in the question THank you for your time Sergio

Ok we went about this a different way and got the right answer...for those of you who may have the same problem... Th, Tc and Qc are given in the problem...isolate Qh using Qh/Th = Qc/Tc to find work W = Qh-Qc thank you for your help marcusl i realized i was going about it the wrong way :)

Hey i have a heat engine that operates in a Carnot cycle between 354.05K and 711.15K, it absorbs 22415J of energy per cycle from hot resevoir. The duration of each cycle is 0.98s. First question was to find the mechanical power output...i calculated this and got W = Qh - Qc = 22415 - 11159.43...

Yes that's exactly the question on my homework page :)

A home is kept cool by an air conditioner. The outside temperature is 311.75K and the interior of the home is 288.55K. If 127kJ/h of heat is removed from the house, what is the minimum power that must be provided to the air-conditioner? answer in kJ/h my work COP = Th / (Th - Tc) = 311.75...

This is one of many postings from me this week :yuck: unfortunately I'm just not getting the correct answers...anyway here I go : A toy balloon is inflated with helium at a constant pressure that is 4.2e5 Pa in excess of atmospheric pressure. If the balloon inflates from a volume of 1.4e-4m3...

Q = heat gained by ice = mcdeltaT = 0.113kg x 2090J/kgdegC x (30.9C-0C) = 7 297.653 J If its not heat gained by the ice...it is lost? therefore the number should be negative? I'm kind of loosing grip on the problem...perhaps I am thinking to much into it I'm assuming you are suggesting to...

so this being said it is -7297.653?

Ok did a little more work and i think i might have the solution, can somebody tell me if I am doing this correctly... using the 8459.268J i calculated for the Q that is left, i did: mass= Q/Lf(of ice) = 8495.268J / 33.5e+4J/kg =0.02525kg (this is amount of ice melted?) using that then i...

I have done some calculations so far but i am kind of stuck, here is the problem: A jar of tea is placed in sunlight until it reaches an equilibrium temp of 32.4 deg C. In an attempt to cool the liquid, which has a mass of 185g, 113g of ice at 0degC is added. Assume specific heat capacity of...

Perfect, ur right i totally forgot about the atmospheric pressure exerted on the piston...I added 1.013x10^5N/m2 to my calculated pressure ...after all the calcs i got 3.26m which makes MUCH more sense and it is correct :D thank you all for your patience... Sergio

I tried doing the same calculations using the corrected pressure equation and came to the answer of 236.38meters (using height = volume / area) and this isn't the correct answer on the homework service...again is it a formula problem i am having? (i tried the calcs a few times over to make sure)...

Ah yes Pressure = Force DEVIDED by area... ...long day :P Thank you OlderDan Sergio

I think I might have this one right but my answer seems kinda high...can somebody help me out...just to confirm A vertical cylinder of cross-sectional area 0.045m2 is fitted with a tight-fitting, frictionless piston of mass 6.5kg. The acceleration of gravity is 9.8 m/s2, andthe universal gas...