Recent content by Sinusoidal

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    Final Net Charge for +23.62µC & 12.82 x 10^{14} Electrons

    So what am I solving for here? Am I solving for q? Do I need to use the q=ne equation? so n=12.82 x 10^{14} electrons, and e=1.6 x 10^{-19}. What is 23.62µC?
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    Final Net Charge for +23.62µC & 12.82 x 10^{14} Electrons

    Homework Statement An item starts with a net positive charge of +23.62µC. A total of 12.82 x 10^{14} electrons are transferred to the object. What is the final net charge? a. +228.7µC b. -181.5µC c. -25.67µC d. +181.5µC Homework Equations q=neThe Attempt at a Solution I'm...
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    Average force the floor exerted on the ball

    Homework Statement A ball of mass 200 g is released from rest at a height of 2.00 m above the floor and it rebounds straight up to a height of 0.900 m. (a) Determine the ball's change in momentum due to its contact with the floor. (b) If the contact time with the floor was 0.0950 seconds, what...
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    What Happens to the Normal Force When the Applied Force is Removed?

    Homework Statement A force of 10.0 N is applied at an angle of 30° to the horizontal on a 1.25-kg block initially at rest on a frictionless surface. a) What is the magnitude of the block’s acceleration? b) What is the magnitude of the normal force? This was en example in my book. I...
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    Acceleration with inclined ramp (Frictionless)

    Okay, that totally makes sense now. Thanks! :)
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    Acceleration with inclined ramp (Frictionless)

    Right, but the first statement still confuses me. Is there a picture you could go by for this?
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    Acceleration with inclined ramp (Frictionless)

    1. What is the acceleration of a skateboard down a ramp inclined at 19.5 degrees to the horizontal? 3.271 is the answer. 2. I know g Sin\vartheta is the equation to get it, but I don't get why it isn't g divided by Sin\vartheta 3. In my head I thought the picture was like...
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