Acceleration with inclined ramp (Frictionless)

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Homework Help Overview

The discussion revolves around calculating the acceleration of a skateboard down a frictionless ramp inclined at 19.5 degrees. Participants are exploring the relationship between gravitational acceleration and the angle of inclination.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for acceleration down an incline, specifically questioning the use of g sin θ versus g/sin θ. There is an exploration of why the latter would yield an illogical result.

Discussion Status

Some participants have provided clarifications regarding the components of gravitational acceleration along the incline. There is an acknowledgment of confusion regarding the initial statements, and a request for visual aids has been made to further understanding.

Contextual Notes

Participants are operating under the assumption that the ramp is frictionless, and there is a noted lack of visual representation to aid in understanding the concepts discussed.

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1. What is the acceleration of a skateboard down a ramp inclined at 19.5 degrees to the horizontal?

3.271 is the answer.




2. I know g Sin[tex]\vartheta[/tex] is the equation to get it, but I don't get why it isn't g divided by Sin[tex]\vartheta[/tex]



3. In my head I thought the picture was like this:
2wew8bq.jpg


I know this should be something super easy, so please explain. haha
 
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g sin theta gives you the component of the acceleration of gravity along the incline.
g/sin theta would give you a number larger than 9.81m/s^2 which would make absolutely no sense.
 
hp-p00nst3r said:
g sin theta gives you the component of the acceleration of gravity along the incline.
g/sin theta would give you a number larger than 9.81m/s^2 which would make absolutely no sense.

Right, but the first statement still confuses me. Is there a picture you could go by for this?
 
This should help you

http://img145.imageshack.us/img145/6905/accelerationvectorgh9.jpg
 
Last edited by a moderator:
Okay, that totally makes sense now. Thanks! :)
 

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