Final Net Charge for +23.62µC & 12.82 x 10^{14} Electrons

[Sinusoidal]

Homework Statement

An item starts with a net positive charge of +23.62µC. A total of 12.82 x 10$$^{14}$$ electrons are transferred to the object. What is the final net charge?

a. +228.7µC b. -181.5µC c. -25.67µC d. +181.5µC

Homework Equations

q=ne

The Attempt at a Solution

I'm confused on how to solve this.

I was thinking n=12.82 x 10$$^{14}$$ electrons, but I don't know which variable +23.62µC would be. Is e supposed to always equal 1.6 x 10$$^{-19}$$?

 

[rl.bhat]

When you transfer electrons to a positively charged body its net positive charge decreases. If the net negative charge of the transferred electrons is more than the positive charge on the body, the body becomes negatively charged.
Yes. e supposed to always equal 1.6 x 10LaTeX Code: ^{-19}

 

[Sinusoidal]

So what am I solving for here? Am I solving for q? Do I need to use the q=ne equation?

so n=12.82 x 10$$^{14}$$ electrons, and e=1.6 x 10$$^{-19}$$. What is 23.62µC?

 

[rl.bhat]

What is the total charge on 12.82X10^14 electrons? It will be negative. From this remove the original positive charge 23.64 micro C. The twill be the remaining charge on the item.