Acceleration with inclined ramp (Frictionless)

  • Thread starter Sinusoidal
  • Start date
  • #1
1. What is the acceleration of a skateboard down a ramp inclined at 19.5 degrees to the horizontal?

3.271 is the answer.




2. I know g Sin[tex]\vartheta [/tex] is the equation to get it, but I don't get why it isn't g divided by Sin[tex]\vartheta [/tex]



3. In my head I thought the picture was like this:
2wew8bq.jpg


I know this should be something super easy, so please explain. haha
 

Answers and Replies

  • #2
g sin theta gives you the component of the acceleration of gravity along the incline.
g/sin theta would give you a number larger than 9.81m/s^2 which would make absolutely no sense.
 
  • #3
g sin theta gives you the component of the acceleration of gravity along the incline.
g/sin theta would give you a number larger than 9.81m/s^2 which would make absolutely no sense.

Right, but the first statement still confuses me. Is there a picture you could go by for this?
 
  • #4
This should help you

http://img145.imageshack.us/img145/6905/accelerationvectorgh9.jpg [Broken]
 
Last edited by a moderator:
  • #5
Okay, that totally makes sense now. Thanks! :)
 

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