Acceleration with inclined ramp (Frictionless)

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1. What is the acceleration of a skateboard down a ramp inclined at 19.5 degrees to the horizontal?

3.271 is the answer.




2. I know g Sin[tex]\vartheta[/tex] is the equation to get it, but I don't get why it isn't g divided by Sin[tex]\vartheta[/tex]



3. In my head I thought the picture was like this:
2wew8bq.jpg


I know this should be something super easy, so please explain. haha
 
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g sin theta gives you the component of the acceleration of gravity along the incline.
g/sin theta would give you a number larger than 9.81m/s^2 which would make absolutely no sense.
 
hp-p00nst3r said:
g sin theta gives you the component of the acceleration of gravity along the incline.
g/sin theta would give you a number larger than 9.81m/s^2 which would make absolutely no sense.

Right, but the first statement still confuses me. Is there a picture you could go by for this?
 
This should help you

http://img145.imageshack.us/img145/6905/accelerationvectorgh9.jpg
 
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Okay, that totally makes sense now. Thanks! :)