Recent content by southernbelle

I got that by solving the kinetic energy equation. I mutiplied both sides by 2 to get rid of the halves. It is actually supposed to read: 4 = Vif^2 + 2V2f^2

Homework Statement In an isolated system, cart1 (with mass = 1 kg and vi1 = 2) has a perfectly elastic collision with cart2 (with mass = 2 kg and vi2 = 0). Find the velocity of cart1 and the velocity of cart2 after the collision. I have to solve this using kinetic energy and momentum...

No, they don't. You're right that was an easy way to check myself.

Homework Statement In an isolated system, cart1 (with mass = 1 kg and vi1 = 2) has a perfectly elastic collision with cart2 (with mass = 2 kg and vi2 = 0). Find the velocity of cart1 and the velocity of cart2 after the collision. Homework Equations 1/2m1vi12 + 1/2m2vi22 = 1/2m1v1f2 +...

Okay, so I evaluated the constants. For the first equation: C = 0 For the second equation C = -1 But how do I plot those? Would I use the coordinates (0,0) and (1, -1) ? I am thinking that the Constant is where you start on the y-axis and then you use the slope to go from there...

Homework Statement For 0<t<1, v(t) = t +3 For 1<t<2, v(t) = 5-t Assume x(o)=0 A) Draw corresponding displacement and acceleration diagrams. B) Determine the equation for each segment Homework Equations Acceleration is the derivative of velocity. Velocity is the derivative of...

Can you explain that a little further? Because I have no idea what you're talking about.

I must differentiate before getting the t value? Because I did differentiate before I got the Vi and Vf values.

Homework Statement On earth, a ball is launched over level ground. It's vertical equation of motion is y(t) = -4.9(t2 - 8t - 20) A) Find tymax and ymax B) Find vyinitial and vyfinal Homework Equations y(t) = Yi + via + 1/2at2 Vf = vi + at The Attempt at a Solution I tried...

Yes, the deflection is 60 degrees. I used 0.5 as the height because that is the length of the string.

I got 3.1 for the v. I did: 1/2mv2 = mgh v2=2gh v2 = 2 [9.8(0.5)] v=3.1m/s Is that correct? Should I have used 0.5 for the height? If that is right, then the acceleration would equal 3.1/0.5 = 6.2 m/s2

Could I use a= gcos60? Although I guess I can use the length of the string as r in the equation ac = v2/r

Okay I understand now, thank you!

The acceleration is usually the derivative of the speed, correct? But I don't think it would be = 0.

Homework Statement An 80 kg man jumps from a height of 2m onto platform mounted on springs. As the springs compress the platform is pushed down a maximum distance of 0.2m below its initial position, and it rebounds. a) What is the man's speed at the instant the platform depressed 0.1m? b)...