Recent content by sss1

Well if the e field is strong, it’ll only take a few cycles until the particle leaves? Whereas if if the e field is weak, it’ll take a long time to leave the cyclotron, so the KE is the same regardless?

For this question part d, KE=mv^2/2=q^2B^2r^2/2m (I rearranged B=mv/qr for v and subbed into mv^2/2). q^2b^2r^2/2m=2F_cyc^2r^2m(pi)^2 But when I subbed the values in I got 16.45MeV but the answer says 165keV instead. I'm not sure what went wrong? What's a good explanation for part e also?

I had a look at the table and tried calculating the spectral radiancy using both frequency and wavelength, but got different answers? I used these two formulas. The wavelength I used was 966e-9m, and so the frequency should be (3e8)/(966e-9) Hz?

Does it work now?

Im getting confused between the differences of all of these formulas. I googled spectral radiance black body and all of the first four pictures came up. They represent the intensity of radiation at a particular wavelength right, or the y-axis of the black body radiation curve? So if I integrate...

Binding energy- the amount of energy required to dissemble the nucleus High binding energy means that the nucleus is very tightly bound, whereas a low binding energy means the nucleus is weakly bound. The nuclear strong force acts at a very short range whereas the Coulomb force is infinite...

What makes sense? The Tin foil and the light bulb?

well tin foil is conductor so electrons rearrange themselves and the e field from the light, since they're EM radiation, cannot propagate. So no light? Whereas paper is an insulator so EM radiation can move through?

so the signal cant propagate because the e field is being canceled out due to the electrons inside the conductor rearranging themselves and the magnetic field in the signal is canceled by Faraday's law eddy currents?

Is this a good response? The lift is a conductor, therefore electrons can move freely. The charges on a conductor reside on the outer surface as they like to be as far from each other as they possibly can be due to the repulsive coulomb force. There is no charge between the inner and the outer...

Oh right, misread it. 200pm?

Needs squaring?

For the problem with the diagram, I'm getting from n=4 to n=2, n=5 to n=4, n=5 to n=1 and n=4 to n=1. n=4 to n=2 corresponds to n=1 to n=2 in well C; n=5 to n=4 corresponds to n=1 to n=2 in well D; n=5 to n=1 corresponds to n=1 to n=3 in well D and n=4 to n=1 corresponds to n=1 to n=2 in well E...

I think its critically damped by looking at the graph of the solution.

Oh I see, they are indeed in the same direction. Thanks! I'll have a look