Recent content by strugglin-physics

That wasn't suppose to be torque but rather tension.

A shop sign weighing 206 N is supported by a uniform 132 N beam of length L = 1.89 m as shown in figure below. The guy wire is connected D = 1.19 m from the backboard. Find the tension in the guy wire. Assume theta = 43.0 o Find the horizontal force exerted by the hinge on the beam. Find...

A 16 kg object is acted on by a conservative force given by F = (-2.9)x + (-4.8)x2, with F in Newtons and x in meters. Take the potential energy associated with the force to be zero when the object is at x = 0. What is the potential energy of the system associated with the force when the object...

So you mean use the formula V=GMm/R+r - GMm/R and that will give me the velocity just before it hits? What about the initial velocity? Does that go in there somewhere?

A meteor has a speed of 83.0 m/s when 811 km above the Earth. It is falling vertically (ignore air resistance) and strikes a bed of sand in which it is brought to rest in 3.31 m. What is its speed just before striking the sand? So here is the formula that I have but it doesn't give me the...

Oh duh that is the Work! So I use W=1/2mv^2! Thanks for the help!

I would believe it to be the Force as that is what the function is.

The force required to compress an imperfect horizontal spring an amount x is given by F = 153x + 12.7x3 , where x is in meters and F in Newtons. If the spring is compressed 1.96 m, what speed will it give to a 3.15 kg ball held against it and then released? I know that I will need to take the...

Wow, I was way off. Thanks for your help, it helped me with another problem I was stuck on to.

A pump is to lift 16.0 kg of water per minute through a height of 3.38 m. What output rating (watts) should the pump motor have? Potential Energy Initial = O Kenetic Energy Final = 0 So, KE-PE = W 1/2mv^2 - mgh = Work 1/2(16.0)(3.38)^2 - (16.0)(9.8)(3.38) = -439 W The fact that my...

Ahh that makes sense. I was trying to figure it out without first finding the work. Thanks

It says that the answer is not 101.4 And the next questions says What is the angle between F and d?

Right, got that part, I think. W=11.5*5.63 + 9.62*3.81 + 13.2*0 = 101.4 cos theta My question is how to find theta. would theta be the inverse tangant of 36.65/64.75?

A force F = (11.5i + 9.62j + 13.2k)kN acts on a small object of mass 109g. If the displacement of the object is d = (5.63i + 3.81j) m, calculate the work done by the force. I know W=F*d*cos theta so W=101.4 cos theta How do I find theta? Do I use the inverse tangant of the F and the d?

Great thank you that was a whole lot easier than I made it out to be!