Solving Hanging Sign Problem: Find Tension, Horizontal & Vertical Force

  • Thread starter Thread starter strugglin-physics
  • Start date Start date
  • Tags Tags
    Sign
AI Thread Summary
The discussion centers on calculating the tension in a guy wire supporting a shop sign and the forces exerted by the hinge on a beam. A sign weighing 206 N is supported by a 132 N beam, with the guy wire connected at a distance of 1.19 m from the backboard and at an angle of 43 degrees. The initial calculations presented for tension and forces are deemed incorrect due to mismatched units and improper torque considerations. Participants emphasize the importance of correctly identifying the forces and their points of action to solve the problem accurately. The conversation highlights the need for clarity in applying physics principles to avoid confusion in calculations.
strugglin-physics
Messages
47
Reaction score
0
A shop sign weighing 206 N is supported by a uniform 132 N beam of length L = 1.89 m as shown in figure below.

The guy wire is connected D = 1.19 m from the backboard. Find the tension in the guy wire. Assume theta = 43.0 o
Find the horizontal force exerted by the hinge on the beam.
Find the vertical force exerted by the hinge on the beam. Use "up" as the positive direction.

I get T = -mg * 1/2L + T*L*sin(43) = T = mg/2sin(40)

Fx = Hx -T cos(43) = 0
Hx = T cos(43)
Fy = Hy -mg + Tsin(43) = 0
Hy = mg - Tsin(43)

But these are incorrect. Where did I go wrong?
 

Attachments

  • gian0959.gif
    gian0959.gif
    5.5 KB · Views: 755
Physics news on Phys.org
"I get T = -mg * 1/2L + T*L*sin(43) = T = mg/2sin(40)"

This is complete nonsense!

You have 3 forces creating torques about the hinge. Which, and where do they act?
 
That wasn't suppose to be torque but rather tension.
 
It's still nonsense, since your units don't match (T and TL have not the same units)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top