Thanks for the replies,
The question states, "determine the magnitude of the vertical force F if the resultant of the three forces acting on the crank passes through the bearing O."
So if it's a crank and the resultant is passing through a bearing then it is not in equilibrium, I am assuming...
540 views and no one person on here can even throw a simple hint my way... I am at a loss as to why. I read the rules and have done everything instructed. What's the deal here?
Homework Statement
Determine the magnitude of F if the resultant of the three forces passes through point O.
Homework Equations
ƩFx = 0
ƩFy = 0
ƩM = 0
The Attempt at a Solution
The most I can come up with is that the two forces on the left would equal F on the right, and...
Replace with equivalent force-couple system??
My book has one page on this and I do not understand what they want...
Please see attached picture for problems..
First one, left side, says replace the 5KN force with an equivalent force-couple system at O.
and
The second one says to...
2: Says, replace the two 5 KN forces with an equivalent system consisting of the 7 KN force applied at C and a second force applied at point D. Determine the magnitude and direction of the second force and the distance CD.
Please see the picture for the FBD.
How I did this.
First I found...
Could someone take a look at what I am working on and tell me if I am on the right track?
#1: Determine the moment of the 200 N force about point B. Please see attached picture for FBD.
First I find the x and y components.
x = 100N y= 173.2N, which are perpendicular and parallel to...
Thanks lots Peter,
At first I was trying to rearrange " 70(cos140o) + 80(cos165o) + 150(cosθ) = 0" for the unknown angle and was frustrated as to why that wouldn't work.
tricky trick question.
Thanks, now I can sleep, lol.
The sum of the horizontal components, in the x direction, is:
70(cos140) + 80(cos165) = -131lb
to take it further;
70(sin140) + 80(sin165) = 66lb
r= (-131)2 + (66)2 = 147 lbs
inverse tan = 66/-131 = -27 degrees(I think I get it now) the resultant is vertical up.. so the sum of the left...
I have tried everything on this one that I can think of.
I understand that the forces in the horizontal are 0, but I don't know where to start.
says: determine the angle for which the resultant of the three forces is vertical. See Picture.