Recent content by SUCRALOSE

Thanks for the replies, The question states, "determine the magnitude of the vertical force F if the resultant of the three forces acting on the crank passes through the bearing O." So if it's a crank and the resultant is passing through a bearing then it is not in equilibrium, I am assuming...

540 views and no one person on here can even throw a simple hint my way... I am at a loss as to why. I read the rules and have done everything instructed. What's the deal here?

Homework Statement Determine the magnitude of F if the resultant of the three forces passes through point O. Homework Equations ƩFx = 0 ƩFy = 0 ƩM = 0 The Attempt at a Solution The most I can come up with is that the two forces on the left would equal F on the right, and...

Replace with equivalent force-couple system?? My book has one page on this and I do not understand what they want... Please see attached picture for problems.. First one, left side, says replace the 5KN force with an equivalent force-couple system at O. and The second one says to...

2: Says, replace the two 5 KN forces with an equivalent system consisting of the 7 KN force applied at C and a second force applied at point D. Determine the magnitude and direction of the second force and the distance CD. Please see the picture for the FBD. How I did this. First I found...

Could someone take a look at what I am working on and tell me if I am on the right track? #1: Determine the moment of the 200 N force about point B. Please see attached picture for FBD. First I find the x and y components. x = 100N y= 173.2N, which are perpendicular and parallel to...

Thanks lots Peter, At first I was trying to rearrange " 70(cos140o) + 80(cos165o) + 150(cosθ) = 0" for the unknown angle and was frustrated as to why that wouldn't work. tricky trick question. Thanks, now I can sleep, lol.

The sum of the horizontal components, in the x direction, is: 70(cos140) + 80(cos165) = -131lb to take it further; 70(sin140) + 80(sin165) = 66lb r= (-131)2 + (66)2 = 147 lbs inverse tan = 66/-131 = -27 degrees(I think I get it now) the resultant is vertical up.. so the sum of the left...

Please see this picture for above question.

I have tried everything on this one that I can think of. I understand that the forces in the horizontal are 0, but I don't know where to start. says: determine the angle for which the resultant of the three forces is vertical. See Picture.

was not my intention to take over this thread, I start a new one. and I still do not get it.

How the hell do you find this angle? see attached pic says: determine the angle for which the resultant of the three forces is vertical.