Just to check my understanding, I think that my arrangement of nodes (4 total) with 2 DOFs each (8 total) leaves me with a 4X8 stiffness matrix. Is that correct?
Alright my attempt at formatting got messed up once I posted. Nodes 2-4-6 are equally spaced across the top, and nodes 1-3-5 sit below 2-4-6 on the bottom. 2-4-6 are respectively connected to 1-3-5 vertically, and 2 is connected to 3 diagonally, and 3 is connected to 6 diagonally.
Howdy,
If I have the following configuration of nodes:
2---4--6
| \ | /|
| \ | / |
| \| / |
| \/ |
1---3--5
What should the dimensions of my FEM stiffness be?
Thanks
Thanks again SteamKing... Do you have any idea how the "tedious" algebra would flow to solve for "a","b", and "c"? I have taken quite a few paths, and I quickly end up in "trivial solution land"...
Thanks a lot for the response SteamKing! The link you posted was very helpful.
I just want to make sure that I understand the notation of the functions correctly:
Does "[N(x,y)] = [Ni(x,y) Nj(x,y) Nk(x,y)]" translate to "Triangle N" with vertices at "Ni(x,y), Nj(x,y) and Nk(x,y)? Is the...
That's how the question was posed to me. I wish I knew more about FEM so that I could provide more insightful detail.
The way I understand things, [N(x,y)] = [Ni(x,y) Nj(x,y) Nk(x,y)] is the shape function, and the other three functions are the basis functions. These shape/basis functions...
Howdy,
I am trying to formulate a proof to show that the shape function
[N(x,y)] = [Ni(x,y) Nj(x,y) Nk(x,y)]
and the the basis functions
Ni(x,y) = (1/2A)(ai + bix + ciz)
Nj(x,y) = (1/2A)(aj + bjx + cjy)
Nk(x,y) = (1/2A)(ak + bkx + cky)
are valid for triangular, 2 dimensional...