The polar equation of given parabola will be ##r=-2a/(1+cos \theta)##. The limit of theta is pi/4 to pi/2. Integrating the expression wrt r I'm left with ##\int_{\pi/4}^{\pi/2} \dfrac{-2a cos 2 \theta}{1+cos \theta} d \theta ##
Homework Statement
Evaluate the integral by changing into polar coordinates.
\displaystyle \int_0^{4a} \int_{y^2/4a}^y \dfrac{x^2-y^2}{x^2+y^2} dx dy The Attempt at a Solution
Substituting x=rcos theta and y=rsin theta , the integrand changes to cos 2 \theta r dr d \theta . I know that the...
I appreciate your effort and patience for posting the complete solution. However, your method was too complex for me. I don't know anything about contours and related terms. The integral which I posted here is a part of another integral which forms the original problem and here's it.
Calculate...
Homework Statement
$$ \displaystyle \int_0^{\infty} e^{-x} \dfrac{a\sin ax - \cos ax}{1+a^2} da $$
Homework Equations
The Attempt at a Solution
Evaluating this using integration by parts will be a cumbersome process and I don't even think that would give me the answer. Substitutions aren't...
Homework Statement
Evaluate \displaystyle \int_0^{\pi} \log (1+a\cos x) dx
Homework Equations
The Attempt at a Solution
Using Leibnitz's Rule,
F'(a)=\displaystyle \int_0^{\pi} \dfrac{\cos x}{1+a \cos x} dx
Now, If I assume sinx=t, then the above integral changes to
\displaystyle \int_0^{0}...
Homework Statement
Find the value of n so that the equation V=r^n(3 \cos ^3 \theta -1) satisfies the relation
$$\dfrac{\partial}{\partial r} \left( r^2 \dfrac{\partial V}{\partial r} \right) + \dfrac{1}{\sin \theta}\dfrac{\partial}{\partial \theta} \left( \sin \theta \dfrac{\partial...