Solve for n: Finding Value of n for Equation V

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SUMMARY

The forum discussion centers on solving for the variable n in the equation V = r^n(3 cos^3 θ - 1) to satisfy a specific partial differential equation (PDE). The derived equation, n(n + 1)(3 cos^3 θ - 1) = 18 cos θ (2 cos^2 θ - 1), indicates that there may be no value of n that satisfies the PDE. Participants emphasize the need for detailed work to identify potential algebraic errors and suggest substituting specific values for θ to explore solutions further.

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utkarshakash
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Homework Statement


Find the value of n so that the equation V=r^n(3 \cos ^3 \theta -1) satisfies the relation
$$\dfrac{\partial}{\partial r} \left( r^2 \dfrac{\partial V}{\partial r} \right) + \dfrac{1}{\sin \theta}\dfrac{\partial}{\partial \theta} \left( \sin \theta \dfrac{\partial V}{\partial \theta} \right)=0$$


Homework Equations



The Attempt at a Solution


The final equation after differentiation comes out to be
$$n(n+1)(3 \cos ^3 \theta -1) = 18 \cos \theta (2\cos ^2 \theta -1) $$

What should I substitute for θ ?
 
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Why should you need to substitute something for theta?
Recheck your algebra... you final relation is saying there is no value of n that will make V satisfy the PDE.
 
Simon Bridge said:
Why should you need to substitute something for theta?
Recheck your algebra... you final relation is saying there is no value of n that will make V satisfy the PDE.


I've already checked it thrice but couldn't find any error! Can you please show me where I'm going wrong?
 
utkarshakash said:
I've already checked it thrice but couldn't find any error! Can you please show me where I'm going wrong?

How can anybody tell where you went wrong? You have not shown your work in detail.

I (or Maple) get something completely different from your result.
 

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