Recent content by wondermoose

Homework Statement In the figure (link below), C1 = 20 \muF, C2 = 24 \muF, C3 = 16 \muF, C4 = 20 \muF, C5 = 22 \muF, and V = 20 V. How much energy is stored by C2? Here's the figure: Homework Equations Q = C\DeltaV Ucap = (1/2)C\DeltaV2 Ceq = C1 + C2 + C3 + ... The Attempt at a Solution...

Okay, here's what I've got. omega = sqrt(k/m) k = omega2*m k=(3.85 rad/s)2(4.5 kg) k=66.7 (units?) Then, k(y0)2 = m(vmax)2 vmax = sqrt((k*y02)/m) vmax = 3.27 m/s Look okay? I'm not sure how rad2*kg/sec2 converts to anything though, in finding the spring constant.

Homework Statement A 4.50 kg weight hangs from a vertical massless ideal spring. When set in vertical motion, the weight obeys the equation y(t)=(8.50 cm)sin[(3.85 rad/s)t-1.40]. What is the maximum speed of the weight? What is the spring constant? Homework Equations Hooke's law: F = -kx...

So does that mean the buoyant force is the same for both blocks, regardless of the density of the material? I guess that makes sense, since both blocks are the same dimensions under the same circumstances. Just to make sure I'm getting this (because I obviously didn't before): The buoyant...

Homework Statement A 20cm^3 block of lead and a 20cm^3 block of copper are completely under water. Each is suspended by a thread so that they both hand at the same height in an aquarium filled with water. Which of the following is true? a) The buoyant force is greater on the lead than on...

Can you explain that a little further? I attempted to use conservation energy, but apparently I'm missing something somewhere along the way and not doing the problem correctly at all. Am I going to find the total kinetic energy of the rod, maybe some kind of K(transitional) + K(rotational)...

Homework Statement A 1.80 m long thing rod is balanced vertically on its tip on the floor. It starts to fall and its lower end does not slip. What is its angular speed just before it hits the floor? Homework Equations 1/3ML^2 L=mvr The Attempt at a Solution When I first started...

Alright, so if K=Fd, and F is constant and d doubles, therefore K doubles. Then, relating back to √(KE/2m), then if K is 2K then the speed (v) would still be √(2/2m). v=√(2/2m) Closer? Thanks

But where does velocity fit into those relationships? I know the .5mv2 is going to come into play somewhere along the way, but I don't know where or how. Thanks, tim!

Alright, so W=Fd F=ma W=m*a*d and a=v/t so W = m*v*d/t deltaK=W 1/2mv^2=m*v*d/t Is that along the right line? I'm so freakin' confused.

Hmm... I don't follow. Do I still use the kinetic energy equation in some regard? Or am I trying to complicate the problem?

Wow, really? That was a slightly modified version of the attempt I made on my test... I didn't actually think I was that close. Thanks!

Homework Statement A 0.75-kg object rests on a horizontal frictionless surface. It is in a position such that it is compressing a spring with a spring constant of 50 N/m. If the object is released, the object leaves the spring at a speed of 2.30 m/s. How far was the spring compressed...

Homework Statement A constant horizontal pull acts on a sled on a horizontal frictionless ice pond. The sled starts from rest. When the pull acts over a distance x, the sled acquires a speed v and a kinetic energy K. If the same pull instead acts over twice this distance, <the sled's speed will...

Homework Statement The orbit of the Space Shuttle is usually circular with an average altitude above the Earth of around 210 miles. The mass of the Space Shuttle on orbit is about 100,000 kg. 1. What is the distance of the Space Shuttle (shuttle) from the center of the Earth? 2...