Mathematical Analysis and Sequences

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Homework Statement



The problem is:
Show that an \rightarrow \infty iff for all \Delta > 0, \existsN such that n \geq N \Rightarrow an \rightarrow \infty

Homework Equations



Not sure if there are any

The Attempt at a Solution



I can't really think of anything to do here because I have absolutely no clue what \Delta is meant to be- my only guess was the difference between the sequences an and aN... and I can't conceptualize this either.

EDIT: I did some google searching, and I understand what this definition means but I have no idea how to approach it. One idea I have is that it is similar to the definition of a limit- I could possibly use something along the lines of a general limit proof to prove this statement.
 
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That really makes no sense. What does "for all \Delta> 0" mean when there was no "\Delta" in the statement of the limit? And what is the difference between \Delta> 0 and n> N?
 
Yeah, so I looked a lot more into it, and it turns out it's just the definition of diverging to infinity except with worser notation. This was word for word a homework probably, btw...
 
Then your homework doesn't make much sense...
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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