What is the film coefficient for a hot object moving through open air?

AI Thread Summary
Estimating the heat transfer coefficient for a hot object moving through open air involves modeling the situation as Newtonian cooling, focusing on convection rather than conduction. The relevant scenario is turbulent flow of a cold gas over a "warm wall," where the coefficient is derived from the Reynolds number. Key parameters include thermal conductivity, length of the object, kinematic viscosity, and velocity. Several questions arise regarding the definitions of terms like "warm wall," the dimensions used for calculations, and the relevance of the object's shape. Clarifying these points is essential for accurate heat transfer modeling in this context.
vhf
Messages
2
Reaction score
0
I'm trying to estimate the heat transfer coefficient from the surface of a hot object moving through open air. After much searching, all I can find is coefficients for sundry fluids confined within the tubes of heat exchangers.

I'm trying to calculate for a body at between 300-460K moving at up to 35m/s through air at about 300K.
 
Physics news on Phys.org
Welcome to PF;
I'd want to model that as Newtonian cooling since the air is moving over the body fast enough to carry the heat away. Objects in air lose heat mostly by convection. You seem to have been looking at heat transfer by conduction.
 
I'm well aware that the problem is one of convection not conduction as are the references on heat exchangers I've been reading.

Out of 60 or so scenarios that are listed, the one that seems to be of closest relevance is turbulent flow of a cold gas over a "warm wall". In this case the Prandtl and Grashof numbers can be disregarded and the coefficient is a function of the Reynolds number:-

P= 0.055k/l R^0.75 (Imperial Units) and R= vL/n where

k= thermal conductivity
l= length of pipe
n= kinematic viscosity
v= velocity
L: "for lengths greater than 2 feet use L=2"


This begs a whole host of questions:-

What exactly does a "warm wall" consist of?
Should I read "length of wall" for length of pipe?
Why are we dividing by l when the transmitted power is already per unit of surface area anyway?
What is the relevant dimension for irregular objects?
Is l the same as L, and if not is "lengths greater than 2 feet" referring to l or L?
Why is R apparently being calculated from a longitudinal rather than a lateral dimension?
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
Back
Top