Equation for half-max contour of 2D Gaussian?

  • Thread starter Thread starter mikeph
  • Start date Start date
  • Tags Tags
    2d Gaussian
AI Thread Summary
The discussion centers on finding the equation for the elliptical contour line at half-max of a 2D Gaussian function defined by G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b. To determine this contour, the half-max value is set to G(x,y) = h/2. The resulting equation for the contour line is derived as (x-x0)^2/a + (y-y0)^2/b = ln(2). Participants express confusion over the calculations, but the key result clarifies the relationship between the Gaussian parameters and the contour line. This provides a clear method for identifying the half-max contour of the Gaussian function.
mikeph
Messages
1,229
Reaction score
18
Hi all,

If I have a Gaussian with the equation:

G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b)

where x0, y0, a, b and h are the parameters which may vary, what's the equation for the elliptical contour line at the half-max of G?

I'm getting myself confused!

Thanks for help
 
Mathematics news on Phys.org
MikeyW said:
G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b)
what's the equation for the elliptical contour line at the half-max of G?
How far did you get? Did you find the max value? Did you plug half that into the equation to see what resulted?
 
I was wondering if there is some standard result that meant I didn't have to do all that.
 
MikeyW said:
Hi all,

If I have a Gaussian with the equation:

G(x,y) = h*exp(-(x-x0)^2/a -(y-y0)^2/b)

where x0, y0, a, b and h are the parameters which may vary, what's the equation for the elliptical contour line at the half-max of G?

I'm getting myself confused!

Thanks for help
G(x,y) = h/2 is what you want.

(x-x0)2/a + (y-y0)2/b = ln2.
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Back
Top