naviakam
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Not sure how to calculate I(V) and E(V).haruspex said:There is clearly no unambiguous way to extract two relationships from the one, but an obvious guess is that in a vacuum the energy would be directly proportional to the voltage, leaving you with a simple way to extract the relationship between voltage and current from the observed data.
But you got different results at some other pressure, so this is not a vacuum. Presumably the gas present saps some of the KE, but should not affect the current.
##E=ItV, V=CI^{4}, Q=KC^{-n}, Y=KE^{-n}##
Then
##Y=Q(I^5tV)^{-n}##
resulted in
##V=(QY)^{-n}(I^5t)^{-1/n}##
where t is the time, E energy, Y intensity, V potential, Q constant, I current.
If correct how it is written more in the math style?
What if the equation in post #39 is considered, how rewritten considering such potential?
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