From solution to mother equation

  • Thread starter Thread starter naviakam
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  • #51
haruspex said:
There is clearly no unambiguous way to extract two relationships from the one, but an obvious guess is that in a vacuum the energy would be directly proportional to the voltage, leaving you with a simple way to extract the relationship between voltage and current from the observed data.
But you got different results at some other pressure, so this is not a vacuum. Presumably the gas present saps some of the KE, but should not affect the current.
Not sure how to calculate I(V) and E(V).

##E=ItV, V=CI^{4}, Q=KC^{-n}, Y=KE^{-n}##
Then
##Y=Q(I^5tV)^{-n}##
resulted in
##V=(QY)^{-n}(I^5t)^{-1/n}##
where t is the time, E energy, Y intensity, V potential, Q constant, I current.
If correct how it is written more in the math style?
What if the equation in post #39 is considered, how rewritten considering such potential?
 
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  • #52
naviakam said:
##E=ItV, ##
Isn't E here the energy of an individual ion?

But I am worried about my earlier interpretation. Your data say the current (ions per unit time) and energy (per ion) are negatively correlated. I cannot imagine what physical set up would lead to that. An applied potential that increases one should increase the other, no?

Is it possible for you to provide a far more detailed description of the apparatus? What is being varied to get the different readings?
 
  • #53
naviakam said:
This data and many others fit well with power law without any curve at the end.
I assume the two columns in the data you posted are respectively x, y.
I just tried plotting y against x-4. Nothing like a straight line.
Please post exactly what power law equation (constants included) you get for the relationship.
 
  • #54
haruspex said:
Isn't E here the energy of an individual ion?

But I am worried about my earlier interpretation. Your data say the current (ions per unit time) and energy (per ion) are negatively correlated. I cannot imagine what physical set up would lead to that. An applied potential that increases one should increase the other, no?

Is it possible for you to provide a far more detailed description of the apparatus? What is being varied to get the different readings?
It is a plasma device called plasma focus consisting a chamber and electrode assembly of anode at the center and cathode around it. capacitor discharge (10 KV) in the gas filled the chamber accelerates the ions to MeV with the spectrum I sent the data earlier. The intensity of low energy ions are high and decreases with energy by ##E^{-n}## where n is around 4.
 
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  • #55
haruspex said:
I assume the two columns in the data you posted are respectively x, y.
I just tried plotting y against x-4. Nothing like a straight line.
Please post exactly what power law equation (constants included) you get for the relationship.
This is another plot with power law fit in origin for the same device:
##Y=KX^{-n}## where ##K=6.8*10^{23}## and ##n=4.56##

1610348696895.png
 
  • #56
naviakam said:
This is another plot with power law fit in origin for the same device:
##Y=KX^{-n}## where ##K=6.8*10^{23}## and ##n=4.56##

View attachment 275997
I need the raw data and the power law equation you believe fits it for the same data.
The fit above doesn't look that great to me.
 
  • #57
haruspex said:
I need the raw data and the power law equation you believe fits it for the same data.
The fit above doesn't look that great to me.
power law was mentioned above and the data is:
1106.16 1.20E+10
1048.02 1.19E+10
994.96 1.27E+10
946.43 1.48E+10
901.95 1.92E+10
861.07 2.17E+10
823.44 2.79E+10
788.72 3.35E+10
756.65 4.31E+10
726.96 5.83E+10
699.44 7.19E+10
673.89 8.53E+10
650.14 9.91E+10
628.04 1.17E+11
607.45 1.32E+11
588.24 1.54E+11
570.31 1.79E+11
553.55 2.07E+11
537.87 2.30E+11
523.20 2.74E+11
509.46 3.13E+11
496.58 3.45E+11
484.51 3.91E+11
473.18 4.23E+11
462.54 4.83E+11
452.56 4.94E+11
 
  • #58
naviakam said:
power law was mentioned above and the data is:
1106.16 1.20E+10
1048.02 1.19E+10
994.96 1.27E+10
946.43 1.48E+10
901.95 1.92E+10
861.07 2.17E+10
823.44 2.79E+10
788.72 3.35E+10
756.65 4.31E+10
726.96 5.83E+10
699.44 7.19E+10
673.89 8.53E+10
650.14 9.91E+10
628.04 1.17E+11
607.45 1.32E+11
588.24 1.54E+11
570.31 1.79E+11
553.55 2.07E+11
537.87 2.30E+11
523.20 2.74E+11
509.46 3.13E+11
496.58 3.45E+11
484.51 3.91E+11
473.18 4.23E+11
462.54 4.83E+11
452.56 4.94E+11
Is this the data that goes with the equation in post #55?
 
  • #59
haruspex said:
Is this the data that goes with the equation in post #55?
Yes.
 
  • #60
##Y=P(p)Y1(E)+(1−P(p))Y2(E)##, where P(6mbar)=0 and P(10mbar)=1.
How to calculate Y(V) and E(V)?
Potential is ##V=YE/It##.
where t is the time, E energy, Y intensity, V potential, I current.
 
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  • #61
naviakam said:
Yes.
One thing this thread has shown me is how hard it can be to discriminate between an exponential and a power law just based on the data.
I went back to your data in post #43 and found very good fits for both types. So I plotted the one against the other over the range of the x values, 460 to 1026. I.e. yexp against ypow where:
##y_{exp}=e^{-\frac x{50}}## and ##y_{pow}=x^{-10}##.
The graph is an excellent fit to ##y_{pow}=2.28*10^{-23}y_{exp}+1.01*10^{-29}##. I found this very hard to believe, but I cannot see any errors in my work.
Of course, it could not remain so straight as x approaches zero since ypow would shoot off to infinity.
Power v Exp.png

I strongly suspect a general principle here, but I haven't figured out the details. Probably something to do with which terms in the expansion of e-λx dominate for a given x.From this I suggest that you should treat all sets of data as being of the same type, either power or exp, and see which fits better overall.
I have to agree that for the data in post #57 power law looks more persuasive than exponential, so maybe take all as being power.Edit:
Tried other powers, an x range of 500 to 1000, and observed a general behaviour that ##x^{-n}## v. ##e^{-knx}## is a pretty straight line where k=0.00128 and n ranges from 4 to 12. But if I change the range of x (still over an octave) it breaks down quite fast; probably need k to be a function of a, where the x range is a to 2a.
 
  • #62
haruspex said:
One thing this thread has shown me is how hard it can be to discriminate between an exponential and a power law just based on the data.
I went back to your data in post #43 and found very good fits for both types. So I plotted the one against the other over the range of the x values, 460 to 1026. I.e. yexp against ypow where:
##y_{exp}=e^{-\frac x{50}}## and ##y_{pow}=x^{-10}##.
The graph is an excellent fit to ##y_{pow}=2.28*10^{-23}y_{exp}+1.01*10^{-29}##. I found this very hard to believe, but I cannot see any errors in my work.
Of course, it could not remain so straight as x approaches zero since ypow would shoot off to infinity.
View attachment 276217
I strongly suspect a general principle here, but I haven't figured out the details. Probably something to do with which terms in the expansion of e-λx dominate for a given x.From this I suggest that you should treat all sets of data as being of the same type, either power or exp, and see which fits better overall.
I have to agree that for the data in post #57 power law looks more persuasive than exponential, so maybe take all as being power.Edit:
Tried other powers, an x range of 500 to 1000, and observed a general behaviour that ##x^{-n}## v. ##e^{-knx}## is a pretty straight line where k=0.00128 and n ranges from 4 to 12. But if I change the range of x (still over an octave) it breaks down quite fast; probably need k to be a function of a, where the x range is a to 2a.
There are many other data sets best fitted with either power law or exponential, therefore ##Y=P(p)Y1(E)+(1−P(p))Y2(E)## still holds.
Considering the potential in post #60, how mathematically Y(V) and E(V) are formulated?
 
  • #63
naviakam said:
There are many other data sets that are best fitted with either power law or exponential, therefore ##Y=P(p)Y1(E)+(1−P(p))Y2(E)## still holds.
Considering the potential in post #60, how mathematically Y(V) and E(V) are formulated?
Please post a dataset which clearly is closer to exponential than to a power law.

##Y=P(p)Y1(E)+(1−P(p))Y2(E)## doesn't work because you have various powers and probably various coefficients in the exponentials.
 
  • #64
haruspex said:
Please post a dataset which clearly is closer to exponential than to a power law.

##Y=P(p)Y1(E)+(1−P(p))Y2(E)## doesn't work because you have various powers and probably various coefficients in the exponentials.
1610618943568.png
 
  • #65
haruspex said:
Please post a dataset which clearly is closer to exponential than to a power law.

##Y=P(p)Y1(E)+(1−P(p))Y2(E)## doesn't work because you have various powers and probably various coefficients in the exponentials.
This is another data fits well with Exp:
1205.36 1.69E+10
1135.78 1.72E+10
1072.51 1.81E+10
1014.83 1.79E+10
962.07 1.81E+10
913.71 1.79E+10
869.25 1.91E+10
828.31 2.04E+10
790.51 2.09E+10
755.54 2.32E+10
723.14 2.73E+10
693.06 2.95E+10
665.08 3.73E+10
639.02 4.24E+10
614.71 5.28E+10
592.01 6.60E+10
570.77 8.40E+10
550.88 1.11E+11
532.22 1.47E+11
514.71 1.86E+11
498.25 2.40E+11
482.77 3.15E+11
468.19 4.00E+11
454.45 5.07E+11
 
  • #66
naviakam said:
This is another data fits well with Exp:
1205.36 1.69E+10
1135.78 1.72E+10
1072.51 1.81E+10
1014.83 1.79E+10
962.07 1.81E+10
913.71 1.79E+10
869.25 1.91E+10
828.31 2.04E+10
790.51 2.09E+10
755.54 2.32E+10
723.14 2.73E+10
693.06 2.95E+10
665.08 3.73E+10
639.02 4.24E+10
614.71 5.28E+10
592.01 6.60E+10
570.77 8.40E+10
550.88 1.11E+11
532.22 1.47E+11
514.71 1.86E+11
498.25 2.40E+11
482.77 3.15E+11
468.19 4.00E+11
454.45 5.07E+11
Again, I get a tolerable fit with either exp or power:
1610672616810.png

I slightly prefer the power fit; it seems to have less of a twist near the origin.

One of the tricky parts about fitting curves to data is that the best fit depends on what you choose to plot against what. E.g. the best least squares fit for ##y=Ae^{kx}## will be different from the best for ##\ln(y)=\ln(A)+kx##. The latter model will put more emphasis on the match for the smaller values of y.
To optimise this, it helps if you have some idea how the accuracy of the measurements varies across the range.

Now, this is not an area I know much about, but I took a look at the black body spectrum formula. I note that this mixes power and exponential, so maybe something similar is going on here.
 
  • #67
haruspex said:
Again, I get a tolerable fit with either exp or power:
View attachment 276269
I slightly prefer the power fit; it seems to have less of a twist near the origin.

One of the tricky parts about fitting curves to data is that the best fit depends on what you choose to plot against what. E.g. the best least squares fit for ##y=Ae^{kx}## will be different from the best for ##\ln(y)=\ln(A)+kx##. The latter model will put more emphasis on the match for the smaller values of y.
To optimise this, it helps if you have some idea how the accuracy of the measurements varies across the range.

Now, this is not an area I know much about, but I took a look at the black body spectrum formula. I note that this mixes power and exponential, so maybe something similar is going on here.

Yes black body spectrum consists of a power term multiplied by exponential. It is intensity against wavelength compared with our case which is intensity against energy. In black body the total power is proportional to ##T^4## where T is temperature, and our potential is proportional to ##I^4## where I is current.

Then, how black body spectrum formula and our spectrum could be related?

Or, back to my first question, how our spectrum could be connected to the potential mathematically?
 
  • #68
naviakam said:
Then, how black body spectrum formula and our spectrum could be related?

Or, back to my first question, how our spectrum could be connected to the potential mathematically?
As I have indicated, I do not know enough about the physics involved to answer questions like that.
Presumably you do have some such understanding, which is why I asked you to show me an example of how some given potential would lead to a particular spectrum. If you cannot do that we're both in the dark.

What I can do is analyse your data and suggest ways to unify the results into a consistent relationship.
How many data sets do you have? If you care to post more I will study them.
 
  • #69
haruspex said:
As I have indicated, I do not know enough about the physics involved to answer questions like that.
Presumably you do have some such understanding, which is why I asked you to show me an example of how some given potential would lead to a particular spectrum. If you cannot do that we're both in the dark.

What I can do is analyse your data and suggest ways to unify the results into a consistent relationship.
How many data sets do you have? If you care to post more I will study them.
As requested in post #62:
considering intensity ##Y=P(p)Y1(E)+(1−P(p))Y2(E)## (where ##Y1## and ## Y2## are the power and exp functions respectively) and potential ##V=YE/It##, how mathematically ##Y(V)## and ##E(V)## are formulated/written?
 
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