Equilibrium Constant Table Method

AI Thread Summary
The discussion centers on understanding the molar ratios in a chemical reaction involving the production of ammonia (NH3) from nitrogen (N2) and hydrogen (H2). To produce 1 mole of NH3, 0.5 moles of N2 and 1.5 moles of H2 are required, based on the stoichiometry of the reaction. Participants clarify that the change in moles reflects the consumption of reactants and the production of products, with negative signs indicating the reactants are being used up. The concept of equilibrium is also touched upon, emphasizing that if NH3 decreases, it implies a reverse reaction where NH3 converts back into its reactants, necessitating an initial amount of NH3 for this process to occur. Overall, the conversation highlights the importance of understanding molar ratios and changes in chemical reactions.
TheRedDevil18
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Hi, I just want someone to explain this table to me please, I am totally confused especially with the Change(mol).
Question below:

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If 1 Mole of NH3 is produced, how many moles of N2 and H2 were used to do that?
Hint: Use the molar ratio.

If you know the initial quantity and the change, you get the quantity at equilibrium.
 
How?, still a bit confused. Could you show me?
 
Is "how" related to the quantity at equilibrium?
This is a simple addition. If you start with X moles and produce Y moles, you have X+Y moles.

Is "how" related to the other part?
Just keep in mind that the total number of atoms (both for N and H) cannot change.
 
I mean the Change, how do they get the change?
 
To produce 2 molecules of NH3, you need 1 molecule of N2 (to have 2 N atoms).
To produce 1 molecule of NH3, you need 1/2 molecule of N2.
To produce 1 mole of NH3 (this is given), you need 1/2 moles of N2.

It is that easy.
 
Okay I understand it now, mole ratio N2:NH3 1/2*1=0.5 and H2:NH3 3/2*1=1.5, the signs are negative because they are being used up right?
 
What would happen if the change is negative for NH3, Would it now mean that NH3 is being reversed back into its reactants and the reactants would be positive?
 
  • #10
You would need some initial NH3 for that.
In that case: Right.
 
  • #11
Okay I think that's it, Thanks for your help
 
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