Package by Air (project time motion)

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A relief airplane is delivering a food package to a small island by dropping it from the air, as landing is not possible. The package is ejected horizontally with a speed less than that of the plane, requiring calculations for its release point and impact distance. The discussion includes determining the horizontal distance from the plane to the island for optimal package landing and finding the velocity vector upon impact. The user initially struggled with the project time motion concepts but eventually solved part A of the problem. The conversation highlights the challenges of understanding projectile motion in a practical scenario.
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A relief airplane is delivering a food package to a group of people stranded on a very small island. The island is too small for the plane to land on and the only way to deliver the package is by dropping it. The airplane flies horizontally with constant speed at an altitude . The package is ejected horizontally in the negative x direction with speed relative to the plane. Assume is v1 less than v0. The positive x and y directions are defined in the figure.

|0000(plane)--->v0
|
|h
|
|__________0000(island)
D

A. If the package were to land right on the island, at what horizontal distance from the plane to the island should the package be released?
B. What is the horizontal distance from the plane to the island when the package hits the ground?
C. Find the velocity vector of the package when it hits the ground.

I found that v0, with respect to the ground is v0x^-v1x^
and that t= sqrt((2h)/g)

I don't know what to do from there...

As you can tell I really don't get project time motion...
 
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I found part A D=(v0-v1)*sgrt(2h/g)
 
never mind I found it out :) i am really stupid...
 
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