Noble Gas Configuration for Uranium: Tips and Tricks to Complete [Rn] 7s2

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The noble gas configuration for uranium is completed as [Rn] 7s2 6d1 5f3. The discussion highlights the stability of the 5f3 configuration, drawing parallels to the stability of half-filled orbitals like 3d5. A misconception about the order of filling orbitals was clarified, noting that 5f should follow 6d in this case. The conversation also touched on the electron loss order in transition metals, specifically regarding Fe3+. Understanding these configurations is essential for grasping the electronic structure of uranium and similar elements.
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Could someone please help me finish the nobel gas configuration for uranium? I get as far as [Rn] 7s2, but I can't figure out what goes next.
 
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What is the reason for this structure? I assume the 5F3 is more stable than 5f4, kind off like the half filled 3d5 taking preference.

On a related note I was looking here http://www.chemguide.co.uk/atoms/properties/ionstruct.html#top, and intuitively I'd though of thought when Fe beomces Fe3+ that a 3d atom would be lost before the 4s atom since that 3d54s2, is more stable than 3d64d1?

note: been a while since I did any chemistry.
 
Ok I see what my mistake was...I had the first part right, but then I kept putting 5f before 6d. In this case, 5f goes afterward, so the configuration is actually [Rn] 7s2 6d1 5f3.

Thanks for the help. :)
 
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