How do I find Q without having a distance r?

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AI Thread Summary
The discussion revolves around solving for the charge (q) of two point charges that repel each other while suspended on threads. The user is unsure how to find the charge without the distance (r) but is guided to use the thread length and angle to determine the effective distance. The forces acting on the charges, including tension, weight, and the electric force, are analyzed, leading to the establishment of equilibrium equations. The conversation emphasizes the importance of considering vector components of forces and rewriting equations to isolate the charge. Ultimately, the user is encouraged to simplify the equations correctly to find the value of q.
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Charges...please help!

Homework Statement



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Two 3.52 g point charges on 7.49-m-long threads repel each other after being equally charged. What is the charge q? (θ=31°.)


Homework Equations


F = KQQ/R^2


The Attempt at a Solution


How do I find Q without having a distance r?
 
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BuBbLeS01 said:
How do I find Q without having a distance r?
You are given the thread length and the angle--use that to figure out the distance.
 
Oh yea...so the length from the center to one of the masses is 3.858 m.
So I can do...
F = K*Q*Q/r^2
F = K*Q^2/ r^2
An wouldn't F = 0 since they cancel each other out?
 
Since the masses are in equilibrium, the net force on each is zero. What forces act on each mass?
 
Tension
 
BuBbLeS01 said:
Tension
That's one force. List them all. (And draw yourself a free body diagram showing how the force act on each mass.)
 
Tension and weight are the forces
 
So do I include the electric force? Like...
T - W + Fel = 0
 
BuBbLeS01 said:
Tension and weight are the forces
Don't forget the electrostatic force!
 
  • #10
Isn't that Fel?
 
  • #11
BuBbLeS01 said:
So do I include the electric force? Like...
T - W + Fel = 0
Yes, but realize that forces are vectors--direction counts. Set up two equations: One for the horizontal components, one for the vertical components. Combine these to solve for the charge.
 
  • #12
X.) TSINθ + qE = 0
y.) TCOSθ - mg = 0

T = mg/COSθ
mg/COSθ * SINθ + qE
q = -mg*TANθ/E
 
  • #13
BuBbLeS01 said:
X.) TSINθ + qE = 0
y.) TCOSθ - mg = 0
I'd write that first equation as:
Tsinθ - qE = 0 (since the force components are in opposite directions)

Realize that E is also a function of q, so rewrite that in terms of k, q, and r (which you figured out).

Otherwise, you are on the right track.
 
  • #14
Okay so I end up with...
-q = -(mg*tanθ) / (kq/r^2)
q = (mg*tanθ) / (kq/r^2)
and the q's cancel?
= (mg*tanθ) / (k/r^2)
 
  • #15
BuBbLeS01 said:
Okay so I end up with...
-q = -(mg*tanθ) / (kq/r^2)
q = (mg*tanθ) / (kq/r^2)
and the q's cancel?
The q's don't cancel. And when you divide by a fraction, simplify the result. (Invert and multiply.)
 

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