Sound Waves, Resonance, and intensity

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When two flutists play together at the same intensity, the resulting sound is not perceived as twice as loud due to the logarithmic nature of human hearing. Instead, the combined sound is approximately 1 dB louder than one flutist playing alone. A doubling of intensity corresponds to an increase of about 3 dB, which highlights the difference between intensity and perceived loudness. The equation for sound level, β = 10 log(I/I₀), can be used to calculate varying intensities. Understanding these concepts is crucial for grasping sound perception in music.
babybeth09
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"If two flutists play ther instuments together at the same intensity, is the sound twice as loud as that of either flutist playing alone at the intensity? Why or why not?"

I know that the answer has something to do with the sensation of loudness being logarithmic in the human ear, but I guess I don't really understand the concept.

Any help is greatly, greatly, greatly appreciated! :smile:
 
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The sound will be 1dB louder, I think (using the original as a reference). Either way, it will not be twice as loud. You already gave the correct answer.
 
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Thanks!
 
Well, the equation for the sound level is:

\beta=10log[\frac{I}{I_o}]

Where I_o=10^-^1^2\frac{W}{m^2}

So you can just plug in values for varying intensities and see.
 
Cool - thank you guys. It's good to have some help because my teacher just gives us the assignment without doing much lecturing or anything, then won't really help us at all, so you guys are life savers!
 
dst said:
The sound will be 1dB louder, I think (using the original as a reference). Either way, it will not be twice as loud. You already gave the correct answer.
A doubling in intensity is about 3 dB as a rule of thumb.

Claude.
 

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