Solving Universal Gravity: Height of Chicago's Sears Tower

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Homework Help Overview

The problem involves determining the height of Chicago's Sears Tower based on a gravimetric measurement that indicates a difference in gravitational acceleration at the top of the building compared to street level. The subject area pertains to gravitational physics and the application of gravitational equations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore various equations related to gravitational force and acceleration, questioning how to relate the change in gravity to the height of the building. Some suggest using the difference in gravitational acceleration to derive relationships involving the Earth's radius and gravitational constant.

Discussion Status

The discussion is active, with participants sharing different approaches and questioning the necessity of certain variables in their calculations. Some guidance has been offered regarding the use of the Earth's radius and gravitational acceleration, but there is no explicit consensus on the best method to proceed.

Contextual Notes

There is some confusion regarding the values used for the Earth's radius and the gravitational constant, as well as the implications of dropping certain variables from the equations. Participants are also navigating the precision of their calculations and the interpretation of their results.

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Homework Statement


A sensitive gravimeter is carried to the top of Chicago's Sears Tower, where its reading for the acceleration of gravity is 0.00136 m/s^2 lower than at street level.

Find the height of the building.

Homework Equations



F = GMm/(r^2)

and maybe

K + U = K_o + U_o

The Attempt at a Solution



don't know where to start!
 
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consider other units for m/s^2
 
Well I think I could use (g - 0.00136) = g_t.

I don't know how I could use this though.
 
wait could I do this :

(9.8 - 0.00136) = GMm/r^2 ?
 
Yes, so you can then write ...

g*r12 = G*M= (g - .00136)*r22
 
LowlyPion said:
Yes, so you can then write ...

g*r12 = G*M= (g - .00136)*r22


what happened to small m

(9.8 - 0.00136)(r^2) = GM (m?)
 
m*g*r12 = G*M*m= m*(g - .00136)*r22

If that makes you happier. It isn't a factor.

F = m*g = GM*m/r2

g = GM/r2
 
so,

let G_t = (9.8-0.00136);

then,

G_t*r^2 = GM

M = G_t*r^2 / G

and r is the radius of the Earth and G is the universal gravity constant.

m ~ 9.3579 * 10 ^ 17

But what does this mean? This is the mass of th building and...
 
In case you didn't notice you don't need G and you don't need M and you don't need m.

You just need re and g.

Building height will be Δr = r2 - r1

where r1 = re
 
  • #10
why is that?
 
  • #11
so

(9.8-0.00136) r^2 = GM

and GM is just dropped? why?
 
  • #12
tnutty said:
so

(9.8-0.00136) r^2 = GM

and GM is just dropped? why?

The answer is because you can.

g*r12 = (g - .00136)*r22

You just need re and g.

Building height will be Δr = r2 - r1

where r1 = re
 
  • #13
OK, i guess.

so

(9.8-0.00136) ( 6.37 * 10^6)^2 = R1;

R1 - R2 = height of tower

R1 ~ 3.976 * 10^14
R2 = (6.37 * 10^6)

right I got 6.37 * 10^6 as the radius of the Earth from my book.
 
  • #14
No.

Try being more careful.

(6378)2 km = 40678884

now multiply by 9.81/(9.81 - .00136) = ...

then take the square root. Then subtract one from the other. Keep as much precision as you can.

Your answer will be less than a km. Multiply by 1000 for meters.
 
  • #15
(6378)^2 = 40678884

ans * 9.81 / (9.81-0.00136) =
40684524.26

sqrt(ans) = 6378.44
??
 
  • #16
confused even more. Dont know where 6378 came from and why
sqrt ( ans * 9.81/(9.81-0.00136) )
...
...
 
  • #17
tnutty said:
confused even more. Dont know where 6378 came from and why
sqrt ( ans * 9.81/(9.81-0.00136) )
...
...

I used radius of Earth as 6378 km. And g you recognize as 9.81
sqrt(ans) = 6378.44
Right.

Now 6378.44 - 6378 = .44 km = 440 m = height of building.
 
  • #18
could you do it out in variables first so I can see what you have done.
Sorry.
 
  • #20
ok thanks
 

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