Compressor Power Equation | Factors & Link

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The discussion focuses on the power equation for compressors, specifically the non-isentropic compressor power equation involving mass flow rate, specific heat, and pressure ratios. Participants clarify that the mass flow rate is crucial and relates to the inlet density. There is a debate about the power requirements of vacuum pumps compared to compressors with different pressure ratios. Additionally, questions arise regarding the conversion of head measurements into differential pressure for fan systems. The conversation highlights the complexity of calculating compressor power and the influence of gas properties on performance.
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Please give me the equation with a link if possible for determining power for a compressor. I know volume x pressure differential / efficiency but I think the gas being compressed also is a factor. Thank you.
 
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From my old thermo notes, a non-isentropic compressor has a power of:

\dot{W} = \frac{\dot{m}C_pT_1}{\eta_c} \left[\left(\frac{P_2}{P_1}\right)^{(\frac{\gamma-1}{\gamma})}-1\right]

You can see the same equation here:
http://www.grc.nasa.gov/WWW/K-12/airplane/compth.html
 
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The site seems to be down at the moment but there are online calculators for recips and centrifs at www.processassociates.com

To to process tools section.
 
Fred, from your equation a vacuum pump that has a 1bar/.01bar pressure ratio needs more power than a compressor that has a ratio of 10bar/1bar? Is m the molecular weight or the volume?
 
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m is mass flow rate.

I'll have to look around a bit, but a vacuum pump most likely will not be applicable here. I'm not sure, I don't deal with them.
 
Hello, I'm working on a model of a fan and I have the characteristic curves Flow/impelled power and flow/total pressure.

I also have the relation of adiabatic compression you have written but it concerns the Head (in meters) and not the mass flowrate. Therefore, my question is : how do you get the outlet pressure of a fan knowing the characteristic curves and the formula with the head ?

More clearly that possible to convert the Head (m) into a differential pressure (Pout-Pin) or even the outlet Pressure of the fan (Pout) ?

Thank you for any idea.
 
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Hi, somebody knows this formula?

HP= Q * 63 * Ln(Pd/Ps)

Is a rare formula that are been used in a pipeline gas.

Thanks.

Felipe

PD: Sorry if I make a mistake in the english, I speak spanish.
 
spiraltooth said:
Fred, from your equation a vacuum pump that has a 1bar/.01bar pressure ratio needs more power than a compressor that has a ratio of 10bar/1bar? Is m the molecular weight or the volume?

\dot{m} is the mass flow rate, & is equal to \rho\dot{V}

ie. work required also depends upon the inlet density.
 
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