Find min, max of an unfamiliar function

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To find the minimum and maximum of the function y=8x^4/(x^2+1)^2 + 4x/(x^2+1) + 1, calculus is required. Setting the derivative to zero leads to solving a fourth-degree polynomial, specifically x^4 - 8x^3 - 1. This polynomial has two real roots that correspond to the maximum and minimum values of the function. Graphing the function can be complex, but finding these critical points analytically is essential. Using calculus techniques will yield the desired extrema.
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Homework Statement



For every x over ℝ, find min, max of following expression

Homework Equations



y=8x4/(x2+1)2+4x/(x2+1)+1

The Attempt at a Solution


I've graphed it but it's really complex. How can I find that points? Thank you so much :)
 
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truongson243 said:

Homework Statement



For every x over ℝ, find min, max of following expression
"every x over ℝ" - this shows up as a box in my browser.
truongson243 said:

Homework Equations



y=8x4/(x2+1)2+4x/(x2+1)+1
I'm assuming that you wrote the right side correctly, where there are three terms, with 1 being a term by itself. Rewrite the right side as a single rational expression. What is the least common denominator?
truongson243 said:

The Attempt at a Solution


I've graphed it but it's really complex. How can I find that points? Thank you so much :)
 
truongson243 said:

Homework Statement



For every x over ℝ, find min, max of following expression

Homework Equations



y=8x4/(x2+1)2+4x/(x2+1)+1

The Attempt at a Solution


I've graphed it but it's really complex. How can I find that points? Thank you so much :)

You need to use Calculus, setting the derivative to zero. That gives you a 4th degree polynomial to solve; its two real roots correspond to the max and min. (They are the roots of the polynomial x4 - 8x3 - 1.)

RGV
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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