Is a Matrix of Only Diagonal Ones Always Equal to its Transpose?

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The transpose of a matrix consisting solely of diagonal ones is indeed equal to its original state. This property holds true for any diagonal matrix, as the definition of a transpose indicates that the elements are mirrored across the diagonal. For a diagonal matrix, non-diagonal elements are zero, ensuring that the transpose retains the same structure. The diagonal elements remain unchanged since they are equal when i equals j. Thus, the assertion that the transpose of such a matrix equals the original is correct.
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Very quick question.

Im 99% sure that the transpose of a matrix of only diagonal ones is always equal to its original state.

Ie
|1000| |1000| T
|0100| |0100|
|0010| = |0010|
|0001| |0001|


So my question is am i correct ?

Thanks in advance.
 
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hi mikedamike! :smile:
mikedamike said:
Very quick question.

Im 99% sure that the transpose of a matrix of only diagonal ones is always equal to its original state.

Ie
Code:
              |1000|       |1000| T
              |0100|       |0100|
              |0010| =    |0010|
              |0001|       |0001|


So my question is am i correct ?

Thanks in advance.

yes, and it works for any diagonal matrix …

(a)Tii = (a)ii :wink:
 
The definition of "transpose" is that if the elements of A are "a_{ij}" then the elements of A^T are a_{ji}. So if all non-diagonal elements are 0, we have a_{ij}= a_{ji}= 0. And, of course, on the diagonal i= j so we still have a_{ij}= a_{ji}.
 
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