How Do You Calculate Mean and Median from a Joint Distribution Table?

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To calculate the mean and median from a joint distribution table, one must first understand the arrangement of the data, where values for Hourly Wage (Y) are listed across the top and Years of Education (X) down the side. The mean for each variable can be found using marginal probabilities, with calculations showing that the mean for X is 14.4 and for Y is 21.61. To find the median, the values need to be ordered, and the middle number identified, but clarification is needed on whether to calculate medians for fixed values of X or Y. The discussion highlights confusion over whether to analyze the entire table or specific subsets for each variable. Understanding the distinction between marginal and joint distributions is crucial for accurate statistical analysis.
Economics2012
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Joint Distribution (Means,Medians...) PLEASE HELP!

Hi, I'm wondering if somebody could help me understand this...
If you have a joint distribution with

Hourly Wage (Y)
Years of Education (X) 9 15 30
10 0.07 0.02 0.01
14 0.10 0.30 0.10
16 0.02 0.10 0.28Sorry the 0.07,0.10 and 0.02 are under the 9 and the 0.02,,0.30 and 0.10 are under 15 etc.

How would you find the mean,median or st dev?

I'm so very confused with this stuff?

Any help would be greatly appreciated?
 
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It is not clear what you want. If you want the mean of everything, just add up all the numbers and divide by the number of items (9). Ti get the median, arrange them in order and take the middle number. To get the variance, first get the average of the squares and then subtract the square of the mean.
 


Well see the table looks a bit odd there Y is along the top and X is along the left hand side.
9,15 and 30 are belong to Y and 10,14 and 16 are belong to X. then the numbers are in the table.
It says find the means, medians and st devs of X and Y.
I did what you said before I posted here, but that would be the whole table wouldn't it?
I'm confused as in how you get one for each, is that what this means?
 


You need to clarify what you want the mean, etc. of. Do you want it over X for fixed Y (3 answers) or over Y for fixed X (also 3 answers) or something else?
 


I found the x and y mean...
u=Ep(x)x

ux=(10)(0.1)+(14)(0.5)+)(16)(0.4) = 14.4 -> mean for X by using the marginals
uy= same procedure I got 21.61.

Do you know how you get the median for this, if you understand what I mean?
 


Economics2012 said:
I found the x and y mean...
u=Ep(x)x

ux=(10)(0.1)+(14)(0.5)+)(16)(0.4) = 14.4 -> mean for X by using the marginals
uy= same procedure I got 21.61.

Do you know how you get the median for this, if you understand what I mean?

Where did 0.1, 0.5, and 0.4 come from?
 
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Adding the x's across and then you get the y's by adding down.
 


It looks like you are asking for the statistics of X independent of Y and the statistics of Y independent of X. ux is then the average wage and uy is the average years. What is the underlying question?
 
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